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mestny [16]
3 years ago
9

How many of the identified objects are not accelerating? a race car going around a circular track at 150 mph a sky diver falling

at a constant speed a heavy box sliding across the floor, after being released a bowling ball colliding with a pin a vibrating guitar string a baseball flying through the air a child swinging on a swing?
Physics
2 answers:
Tanya [424]3 years ago
7 0

Answer:

only one: a sky diver falling at a constant speed

Explanation:

Let's recall that acceleration is a change in velocity, which means either a change in the speed of an object or a change in its direction.

let's now analyze each situation:

- a race car going around a circular track at 150 mph --> here the direction of motion is changing, so the object is accelerating

a sky diver falling at a constant speed --> here both the speed and the direction are constant, so the object is NOT accelerating

- a heavy box sliding across the floor, after being released  --> here the speed is changing (In particular, it will decrease, as the friction will slow down the box), so the object is accelerating

- a bowling ball colliding with a pin --> here the speed is changing (when the ball colides with the pin, it slows down), so the object is accelerating

- a vibrating guitar string --> the speed of the vibrating string changes during the vibration (and the direction as well), so the object is accelerating

- a baseball flying through the air --> the speed of the baseball is changing (because there are unbalanced forces acting on the flying ball: the gravity and the air resistance), so the object is accelerating

- a child swinging on a swing --> the speed of the child is changing (and the direction as well) during the oscillation, so the object is accelerating


So, there is only 1 situation in which objects are NOT accelerating:

a sky diver falling at a constant speed

Nonamiya [84]3 years ago
3 0
A race car, sky diver.
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Answer:

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Explanation:

It is given that,

The mass of the car and riders is, m=3\times 10^3\ kg

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Time, t = 8.59 seconds

We need to find the  average net force exerted on the car and riders by the magnets. It can be calculated using second law of motion as :

F = m a

F=m(\dfrac{v-u}{t})

F=3\times 10^3\ kg\times (\dfrac{43.4\ m/s-0}{8.59\ s})

F = 15157.15 N

So, the average net force exerted on the car and riders by the magnets. Hence, this is the required solution.

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Researchers in the Antarctic measure the temperature to be -32°F. What is this temperature on the following scales?(a) the Celsi
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Explanation:

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\begin{gathered} T_c=\frac{5}{9}(-32-32) \\  \\ T_c=\frac{5}{9}(-64) \\  \\ T_c=-35.6^0C \end{gathered}

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8 0
1 year ago
Your friend has decided to make some money during the next State Fair by inventing a game of skill. In the game as she has devel
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Answer: from the vertical, one should aim  86.6°

Explanation:

height of the center of object = 7.0 m - 0.05 m = 6.95 m

now let the bullet hits centre at point A height x meters from the ground

also let t be the time taken for the bullet to hit the object

so distance travelled by the target will be

d = h - x = 6.95 - x

now using the equation of motion

d = 1/2gt²

so 1/2gt² = 6.95 - x

x = 6.95 - 1/2gt² .........let this be equ 1

let angle of fire be ∅

so v(cos∅) × t = 100

our velocity v is 1200 ft/sec = 365.76 m/s

365.76(cos∅) × t = 100 ........equ 2

also vertical position of the bullet after t is

y = y₀ + c(sin∅)t - 1/2gt²

y = 1 + 365.76(sin∅)t - 1/2gt² ----- equ 3

After time t. the vertical position x and y are same, else the bullet wouldn't have strike target at centre, so;

x = y

we substitute

equ 1 = equ 3

6.95 - 1/2gt² = 1 + 365.76(sin∅)t - 1/2gt²

6.95 - 1 = 365.76(sin∅)t - 1/2gt² +  1/2gt²

5.95 = 365.76(sin∅)t

t = 5.96 / 365.76(sin∅)

now input the above equ  into equ 2

365.76(cos∅) ×  5.96/365.76(sin∅) = 100

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tan∅ = 5.95/100 = 0.0595

∅ =  3.40°

therefore from the vertical, one should aim (90° - 3.40°) = 86.6°

4 0
3 years ago
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