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mestny [16]
4 years ago
9

How many of the identified objects are not accelerating? a race car going around a circular track at 150 mph a sky diver falling

at a constant speed a heavy box sliding across the floor, after being released a bowling ball colliding with a pin a vibrating guitar string a baseball flying through the air a child swinging on a swing?
Physics
2 answers:
Tanya [424]4 years ago
7 0

Answer:

only one: a sky diver falling at a constant speed

Explanation:

Let's recall that acceleration is a change in velocity, which means either a change in the speed of an object or a change in its direction.

let's now analyze each situation:

- a race car going around a circular track at 150 mph --> here the direction of motion is changing, so the object is accelerating

a sky diver falling at a constant speed --> here both the speed and the direction are constant, so the object is NOT accelerating

- a heavy box sliding across the floor, after being released  --> here the speed is changing (In particular, it will decrease, as the friction will slow down the box), so the object is accelerating

- a bowling ball colliding with a pin --> here the speed is changing (when the ball colides with the pin, it slows down), so the object is accelerating

- a vibrating guitar string --> the speed of the vibrating string changes during the vibration (and the direction as well), so the object is accelerating

- a baseball flying through the air --> the speed of the baseball is changing (because there are unbalanced forces acting on the flying ball: the gravity and the air resistance), so the object is accelerating

- a child swinging on a swing --> the speed of the child is changing (and the direction as well) during the oscillation, so the object is accelerating


So, there is only 1 situation in which objects are NOT accelerating:

a sky diver falling at a constant speed

Nonamiya [84]4 years ago
3 0
A race car, sky diver.
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A helicopter is moving horizontally to the right at a
In-s [12.5K]

Answer:

Explanation:

Given

Weight of helicopter W=53800 N

inclination of blades with vertical \theta =21^{\circ}

Suppose F_l is the lifting Force

Now using F-B-D

F_{net}=0 as helicopter is moving with constant velocity

balancing forces in Vertical Force

F_l\cos \theta -W=0

F_l\cos \theta =W

F_l=\frac{W}{\cos \theta }

F_l=\frac{53800}{\cos 21}

F_l=57,627.6\ N

Now sin component of lift is air resistance

F_l\sin \theta -R=0

where R=air resistance

R=F_l\sin \theta

R=57,627.6\times \sin (21)

R=20,651.88\ N

 

8 0
3 years ago
What is the resultant force of the free body diagram?
GaryK [48]

1) Magnitude of the net force: 20.8 N

2) Angle: 35.2^{\circ} clockwise from positive x-direction

Explanation:

1)

First of all, we need to find the components of the resultant force along the horizontal and vertical direction.

We observe that there are two forces acting along the horizontal direction:

F_1=33 N\\F_2 = 16 N

We notice that they act in opposite directions, so the net force in the horizontal direction is the difference between these two forces:

F_x =F_1-F_2=33-16=17 N (to the right)

Instead, there is only one force acting in the vertical direction, so the net force in the vertical direction is:

F_y=F_3=12 N (downward)

Therefore, the magnitude of the net force can be found by using Pythagorean's theorem:

F=\sqrt{F_x^2+F_y^2}=\sqrt{17^2+12^2}=20.8 N

2)

Now we have to find the angle of the resultant net force. We can do it by using the following equation:

tan \theta = \frac{F_y}{F_x}

where

\theta is the angle, measured as clockwise from the positive x-direction (because the vertical net force is downward)

F_y = 12 N is the vertical net force

F_x=17 N is the horizontal net force

Solving, we find:

tan \theta=\frac{12}{17}=0.706

And so the angle is

\theta=tan^{-1}(0.706)=35.2^{\circ}

In a direction down with respect to the right.

Learn more about forces:

brainly.com/question/11411375

brainly.com/question/1971321

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About addition of vectors:

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#LearnwithBrainly

4 0
3 years ago
a stationary wave of fundamental frequency has a frequency of 120 hz has been generated in a medium calculate three lighter freq
DENIUS [597]

Answer:

hope it helps

Explanation:

8 0
2 years ago
A couch of mass 210 kg is being pushed across the floor with an applied force of 4100 N. The coefficient of kinetic friction bet
Dennis_Churaev [7]
Let us use the formula for Newton's Second Law of Motion:

Net force = Mass*Acceleration
Net force = Applied Force - μ*Normal Force
where μ is the coefficient of kinetic friction

Normal Force = Force due to gravity = mass*gravity
Normal Force = (210 kg)(9.81 m/s²) =<em> 2,060.1 N</em>

Then,
Net force = 4100 - 0.38*2060.1 = 3317.162 N

3317.162 N = (210 kg)(a)
Solving for acceleration,
<em>a = 15.796 m/s²</em>
8 0
4 years ago
Three Carnot engines operate between the following temperature limits.
Kipish [7]

Answer:c>a>b

Explanation:

Given

All the engine extracts same amount of heat(Q) from High-temperature reservoir

For a) 400 and 500 K

\eta _{engine}=1-\frac{T_L}{T_H}

\eta _{engine}=\frac{work\ supplied}{heat\ supplied}

1-\frac{400}{500}=\frac{W_a}{Q}

W_a=\frac{Q}{5}

For b)500 K and 600K

1-\frac{500}{600}=\frac{W_b}{Q}

W-b=\frac{Q}{6}

For c) 400 K and 600 K

1-\frac{400}{600}=\frac{W_c}{Q}

W_c=\frac{2Q}{3}

So c will give the highest amount of work

c>a>b

6 0
3 years ago
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