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3 years ago

How are the electron structures of boron (B) and aluminum (Al) similar?

2 answers:

4 0

The electron structures of boron and aluminum are similar because they share the same group, therefore they have the same amount of valence electron.

lbvjy [14]3 years ago

3 0

Answer:

- Both of their valence electrons are at p subshell.

- They have the first subshell full of electrons.

- Both of them have just 1 electron at the last p subshell.

Explanation:

Hello,

In this case, we could understand their electron structures by identifying their electron configurations as shown below:

$B^5\rightarrow 1s^2,2s^2,2p^1\\Al^{13}\rightarrow 1s^2,2s^2,2p^6,3s^2,3p^1$

In such a way, we could notice the following similarities:

- Both of their valence electrons are at p subshell.

- They have the first subshell full of electrons.

- Both of them have just 1 electron at the last p subshell.

Best regards.

You might be interested in

What is the relationship between the amount of substance ( concentration) and reaction rates?

jekas [21]

Answer:

Increasing the concentration of the reagents makes the collision between two molecules of the reagents more likely, thereby increasing the probability that the reaction will occur between these reagents.

As for the relationship between concentration and volume, density also comes into play, a higher volume, lower molarity and also lower concentration.

The pressure when increasing could generate a closer approach between the particles, therefore generating an increase in the reaction speed.

Pressure and volume are related but inversely proportional, therefore if the volume increases the pressure decreases and so on.

the reaction rate increases as the contact surface area increases. This is due to the fact that more solid particles are exposed and can be reached by reactant molecules.

A perfect reaction where the collision is promoted and the reaction speed advances is with the presence of a solvent, with an increase in pressure and a decrease in volume, with an increase in the exposure of the surface, with the presence of a catalyst, with increasing temperature and with increasing entrance

Explanation:

The reaction rate is defined as the amount of substance that is transformed into a certain reaction per unit of volume and time. For example, the oxidation of iron under atmospheric conditions is a slow reaction that can take many years but over time it is oxidized sooner or later by the oxygenation of its surface layer, but the combustion of butane in a fire is a reaction that happens in fractions of seconds, giving rise to an exothermic reaction with products such as CO2 and H2O

5 0

3 years ago

Convert 8.876 × 10^12 m^2 to units of km^2.

Darya [45]

Answer:

$8.876\times 10^{18}\ km^2$

Explanation:

In this problem, we need to convert $8.876 \times 10^{12}\ m^2$ to km².

We know that,

1 km = 1000 m

⇒ 1 km² = 10⁶ m²

So,

$8.876 \times 10^{12}\ m^2=8.876 \times 10^{12}\times 10^6\ km^2\\\\=8.876\times 10^{18}\ km^2$

So, $8.876 \times 10^{12}\ m^2$ is equal to $8.876\times 10^{18}\ km^2$ .

7 0

3 years ago

Which development was a direct result of the

gladu [14]

"(2) increase in suburbanization" was a direct result of the <span>baby boom that followed World War II, but of course there were other factors that resulted as well. </span>

3 0

3 years ago

Methyl salicylate is a common active ingredient in liniments such as ben-gay. It is also known as oil of wintergreen. It is made

arlik [135]

Answer: The empirical formula is $C_3H_3O$ .

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2$ = 12.24 g

Mass of $H_2O$ = 2.505 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 12.24 g of carbon dioxide, = $\frac{12}{44}\times 12.24=3.338g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 2.505 g of water, = $\frac{2}{18}\times 2.505=0.278g$ of hydrogen will be contained.

Mass of oxygen in the compound = (5.287) - (3.338+0.278) = 1.671 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{3.338g}{12g/mole}=0.278moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.278g}{1g/mole}=0.278moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{1.671g}{16g/mole}=0.104moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.278}{0.104}=3$

For H = $\frac{0.278}{0.104}=3$

For O = $\frac{0.104}{0.104}=1$

The ratio of C : H : O = 3: 3: 1

Hence the empirical formula is $C_3H_3O$ .

5 0

3 years ago

3. The complex ion Co(H2O)6 2(aq) is pink when placed in solution. Addition of chloride ions creates an equilibrium with CoCl42-

mart [117]

Answer:

See explanation

Explanation:

When the complex ion Co(H2O)6 2+(aq) is placed in solution and chloride ions are added, the following equilobrium is set up;

Co(H2O)62+(aq) + 4 Cl-(aq) <=> CoCl42-(aq) + 6 H2O(g)

Co(H2O)6 2+(aq) solution is pink in colour while CoCl42-(aq) solution is blue in colour.

Since the solubility of CoCl42-(aq) is endothermic, heating the solution will move the equilibrium position towards the right (more CoCl42-(aq) is formed and the solution is blue in colour).

When the solution is cooled, more Co(H2O)62+(aq) is formed and the equilibrium position shifts towards the left and the solution becomes pink in colour.

6 0

3 years ago