Answer:
S = Vo t + 1/2 a t^2 distance traveled
t = (V2 - V1) / a = (0 - 21) / -3.5 = 6 sec time to stop
S = 21 * 6 - 3.5 * 6^2 / 2 = 63 m distance traveled
<h3><u>Answer</u>;</h3>
$347.22
<h3><u>Explanation</u>;</h3>
Principal = $14,200
Rate = 8.5%
Time = 105 days = 105/365
Interest = Principal x Rate x Time
Interest = 14,200 x 0.085 x 105/365
Interest = 347.219
= $347.22
Answer:
Explanation:
From the question we are told that mass
Thin layer radius 
Generally the expression for ths solution is given as
Xcm =(m*0 =m(-2R))/2m =-mR/(2m)=-R/2
the center of mass will not move at initial state
Considering the center of mass of both bodies


Therefore the enclosing layer moves
<h3><u>Answer</u>;</h3>
= F0 L ( 1 - 1/e )
<h3><u>Explanation;</u></h3>
Work done is given as the product of force and distance.
In this case;
Work done = ∫︎ F(x) dx
= F0 ∫︎ e^(-x/L) dx
= F0 [ -L e^(-x/L) ] between 0 and L
= F0 L ( 1 - 1/e )