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Setler79 [48]
4 years ago
5

What happens when an experiment with new information or new technology produces results that support an existing theory?

Physics
2 answers:
AlexFokin [52]4 years ago
6 0

The answer is B ; the theory is updated or revised

trapecia [35]4 years ago
3 0
The theory is revised or updated
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A roller coaster, traveling with an initial speed of 21 m/s, decelerates uniformly at -3.5
liberstina [14]

Answer:

S = Vo t + 1/2 a t^2       distance traveled

t = (V2 - V1) / a = (0 - 21) / -3.5 = 6 sec       time to stop

S = 21 * 6 - 3.5 * 6^2 / 2 = 63 m        distance traveled

3 0
1 year ago
Find the interest. A 105-day note for $14,200 at 8.5% interest.
mr Goodwill [35]
<h3><u>Answer</u>;</h3>

$347.22

<h3><u>Explanation</u>;</h3>

Principal = $14,200

Rate = 8.5%

Time = 105 days = 105/365

Interest = Principal x Rate x Time

Interest = 14,200 x 0.085 x 105/365

Interest = 347.219

             = $347.22

7 0
4 years ago
A ball of radius R and mass m is magically put inside a thin shell of the same mass and radius 2R. The system is at rest on a ho
dlinn [17]

Answer:

x =\frac{-R}{2}

Explanation:

From the question we are told that mass

Thin layer radius = 2R

Generally the expression for ths solution is given as

Xcm =(m*0 =m(-2R))/2m =-mR/(2m)=-R/2

the center of mass will not move at initial state  

Considering the center of mass of both bodies

xcm=\frac{m*x+m*x)}{2m} =x

x =\frac{-R}{2}

Therefore the enclosing layer moves x =\frac{-R}{2}                          

7 0
3 years ago
What is an exothermic chemical reaction? A. It is a reaction that converts matter to heat. B. It is a reaction that requires hea
nordsb [41]

it is D exo means realease

3 0
3 years ago
Read 2 more answers
How much work does this force do as the particle moves along the x-axis from x = 0 to x = l? express your answer in terms of the
nydimaria [60]
<h3><u>Answer</u>;</h3>

= F0 L ( 1 - 1/e )

<h3><u>Explanation;</u></h3>

Work done is given as the product of force and distance.

In this case;

Work done  = ∫︎ F(x) dx  

                    = F0 ∫︎ e^(-x/L) dx  

                    = F0 [ -L e^(-x/L) ] between 0 and L  

                    = F0 L ( 1 - 1/e )

3 0
4 years ago
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