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Gala2k [10]
2 years ago
8

A frictionless toy car is placed on a ramp, which is inclined at an unknown angle with respect to the horizontal. Starting from

rest, the car is allowed to roll freely down the ramp. After a time interval of Δ=0.67 s, the car has traveled a distance of =1.2 m down the ramp and is moving with speed f. Find the speed of the car at the end of the 0.67 s time interval.
Physics
1 answer:
NikAS [45]2 years ago
6 0

The final speed of the toy car at the end of the given time period is 3.58 m/s.

The given parameters;

  • distance traveled by the car, s = 1.2 m
  • time of motion of the car, t = 0.67 s
  • initial velocity of the car, u = 0

The acceleration of the car is calculated as;

s = ut + \frac{1}{2} at^2\\\\1.2 = 0 + 0.5\times a\times (0.67)^2\\\\1.2 = 0.225a\\\\a = \frac{1.2}{0.225} \\\\a = 5.33 \ m/s^2

The final velocity of the toy car is calculated as;

v_f^2 = u^2 + 2as\\\\v_f^2 = 0 + 2\times 5.33 \times 1.2\\\\v_f^2 = 12.792\\\\v_f = \sqrt{12.792} \\\\v_f = 3.58 \ m/s

Thus, the final speed of the toy car at the end of the given time period is 3.58 m/s.

Learn more here: brainly.com/question/20352766

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Kinetic energy

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For example, when you pedal your bicycle so that its speed increases, you are doing work to transfer chemical energy from your muscles to the kinetic energy of the bicycle.

Kinetic energy is the energy an object possesses by virtue of its movement. The amount of kinetic energy possessed by a moving object depends on the mass of the object and its speed. The greater the mass and the speed of the object the greater its kinetic energy.

The kinetic energy Ek of an object of mass m at a speed v is given by the relationship

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For example, suppose you lift a suitcase of mass m through a height h. The weight W of the suit case is a downward force of size mg. In lifting the suitcase, you would have to pull upwards on it with a force equal in size to its weight, mg.

Two suitcases. One has a green force arrow pointing up labelled F and a purple force arrow pointing down labelled 'Weight = mg'. The other case is raised by a height labelled h.

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When this force (equal to the weight mg, but upwards) is applied to the suitcase over the distance h:

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This is the relationship used to calculate gravitational potential energy.

{E_p} = mgh

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