All categories

3 years ago

Before using any chemical in the lab, Way should One first read the material safety data sheet?

1 answer:

8 0

You read the SDS so you know what the hazards are working with the chemicals in the experiment and what precautionary measures should be taken. You wouldn't want to spill sensitizer or corrosive chemicals all over your hands or breath in carcinogens or chemicals that effect the central nervous system. The SDS will tell you what personal protective equipment you should use like the type of gloves, or whether or not you should work in a fume hood.

You might be interested in

If you were to look up at the moon and see the shape of the moon as a circle, what would the next observable shape in the cycle

Vlada [557]

Answer:

half a moon or a quarter moon

4 0

3 years ago

Read 2 more answers

***50 points***<br><br> Magnesium reacts with aluminum chloride

charle [14.2K]

Mg+alcl3-->mgcl2+al is the

6 0

3 years ago

Identify the unit cell that has a = B = y = 90°.

elixir [45]

Monoclinic I think. I'm not sure

8 0

3 years ago

Which part of a root transport water and nutrients

Aleks [24]

xylem of the roots transfers water and nutrients from soil to the different parts of plant.

6 0

3 years ago

Read 2 more answers

04.05 mol

victus00 [196]

Answer:

34.8 g

Explanation:

Answer:

We have the masses of two reactants, so this is a limiting reactant problem.

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

Mᵣ: 123.90 70.91 208.24

P₄ + 20Cl₂ ⟶ 4PCl₅

Mass/g: 46.0 32.0

2. Calculate the moles of each reactant

$\text{moles of P}_{4} = \text{46.0 g P}_{4} \times \dfrac{\text{1 mol P}_{4}}{\text{123.90 g P}_{4}} = \text{0.3713 mol P}_{4}\\\\\text{moles of Cl}_{2} = \text{32.0 g Cl }_{2} \times \dfrac{\text{1 mol Cl }_{2}}{\text{70.91 g Cl }_{2}} = \text{0.4513 mol Cl }_{2}$

3. Calculate the moles of PCl₅ we can obtain from each reactant

From P₄:

The molar ratio is 4 mol PCl₅:4 mol P₄

$\text{Moles of PCl}_{5} = \text{0.3713 mol P}_{4} \times \dfrac{\text{4 mol PCl}_{5}}{\text{4 mol P}_{4}} = \text{0.3713 mol PCl}_{5}$

From Cl₂:

The molar ratio is 4 mol PCl₅:20 mol Cl₂

$\text{Moles of PCl}_{5} = \text{0.4513 mol Cl}_{2}\times \dfrac{\text{4 mol PCl}_{5}}{\text{20 mol Cl}_{2}} = \text{0.090 26 mol PCl}_{5}$

4. Identify the limiting and excess reactants

The limiting reactant is chlorine, because it gives the smaller amount of PCl₅.

The excess reactant is phosphorus.

5. Mass of excess reactant

(a) Moles of P₄ reacted

The molar ratio is 1 mol P₄:20 mol Cl₂

$\text{Moles reacted} = \text{0.4513 mol Cl}_{2} \times \dfrac{\text{4 mol P}_{4}}{\text{20 mol Cl}_{2}} = \text{0.090 26 mol P}_{4}$

(b) Mass of P₄ reacted

$\text{Mass reacted} = \text{0.090 26 mol P}_{4} \times \dfrac{\text{123.90 g P}_{4}}{\text{1 mol P}_{4}} = \text{11.18 g P}_{4}$

(c) Mass of P₄ remaining

Mass remaining = original mass – mass reacted = (46.0 - 11.18) g = 34.8 g P₄

4 0

3 years ago