Each is a zone of decreasing water vapor content within the atmosphere. ... Each is an interface between two layers of the atmosphere. Each is a point of maximum temperature in its layer of the atmosphere.
The object would have a centripetal acceleration <em>a</em> of
<em>a</em> = (12 m/s)² / (0.7 m) ≈ 205.714 m/s²
so that the required tension in the string would be
<em>T</em> = (0.5 kg) <em>a</em> ≈ 102.857 N ≈ 100 N
(rounding to 1 significant digit)
Answer:
The answer is 3,064x
Explanation:
When the collision happens, the momentum of the first car is applied to the both of them.
So we can calculate the force that acts on both cars as:
- The momentum of the first car is P = 2020 kg x 14.2 m/s = 28,684 kg.m/s
- The acceleration of both cars after the crash is going to be a = P / mtotal which will give us a = 28,684 / (2020+2940) = 5.78 m/s
- Since the second car was initially not moving, the final acceleration was calculated with the momentum of the first car.
Now we can find the force that acts on both of them by using the formula F = m.a which will give us the result as:
- F = (2020+2940) x 5.78 = 28,684
The friction force acts in the opposite direction and if they stop after moving 2.12 meters;
- Friction force is Ff = μ x N where μ is the friction coefficient and the N is the normal force which is (2020+2940) x 10 if we take gravitational force as 10, equals to 49,600.
- F - Ffriction = m x V
- 28,684 - μ x 49,600 = 4960 x 5.78
- μ = 3,064x

The number of oscillations of the toy in a second is 1.25.
<h3>What is frequency?</h3>
- This is the number of complete oscillation of an object is a given period.
The given parameter:
- Frequency of the toy, F = 1.25 Hz
The frequency of an object is calculated as follows;

where;
- n is the number of oscillations
- t is the time of motion
The number of oscillations of the toy in a second is calculated as follows;

Learn more about frequency here: brainly.com/question/10728818