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3 years ago

Question 11 (3 points)

Chemistry

1 answer:

Ugo [173]3 years ago

4 0

Answer:

The outer core of the earth is liquid.

Explanation:

Seismic waves travel through the Earth at different speeds and are reflected and refracted diffracted differently as they encounter layers of different densities.

By analyzing these waves, they have concluded that there is an inner core of solid iron surrounded by a liquid outer core consisting of nickel and iron.

A is wrong. The Earth consists of several layers

C is wrong. Seafloor spreading is caused by the movement of tectonic plates away from each other.

D is wrong. The mantle is mostly solid rock.

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Answer:

a. Change of state

Explanation:

Because you will see that the state has changed

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2 years ago

Write the chemical formula for the cation present in the aqueous solution of cuso4.

Inessa05 [86]

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The ions present in the aqueous solution of $CuSO_4$ are $Cu^{2+}$ and $SO_{4}^{2-}$ .

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3 years ago

After a big game, you put your water bottle inside the refrigerator. The next

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Mostly and for what I would say is A

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3 years ago

Which statement best describes visible light?

tekilochka [14]

Answer:

The Visible Spectrum Visible light is the light that we can see, and thus is the only light detectable by the human eye. White light is visible light, and it contains all the colors of the rainbow, from red to violet. The range of visible wavelengths is 400 to 700 nanometers.

Explanation:

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2 years ago

If 1.50 L of 0.780 mol/L sodium sulfide is mixed with 1.00 L of a 3.31 mol/L lead(II) nitrate solution, what mass of precipitate

NARA [144]

Answer:

336.1 g of PbS precipitate

Explanation:

The equation of the reaction is given as;

Na2S(aq) + Pb(NO3)2(aq) ----> 2NaNO3(aq) + PbS(s)

Ionically;

Pb^2+(aq) + S^2-(aq) -----> PbS(s)

Number of moles of sodium sulphide= concentration of sodium sulphide × volume of sodium sulphide

Number of moles of sodium sulphide= 0.780 × 1.5 = 1.17 moles

Number of moles of lead II nitrate= concentration of lead II nitrate × volume of lead II nitrate

Number of moles of lead II nitrate= 3.31× 1.00= 3.31 moles

Then we determine the limiting reactant. The limiting reactant yields the least amount of product.

Since 1 moles of sodium sulphide yields 1 mole of lead II sulphide

1.17 moles of sodium sulphide also yields 1.17 moles of lead II sulphide

Hence sodium sulphide is the limiting reactant.

Thus mass of precipitate formed= amount of lead II sulphide × molar mass of sodium sulphide

Molar mass of lead II sulphide= 287.26 g/mol

Mass of lead II sulphide = 1.17 moles × 287.26 g/mol

Mass of lead II sulphide= 336.1 g of PbS precipitate

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3 years ago