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ira [324]
3 years ago
12

B c_ - _a b( a=3 b=-5 c=6)​

Physics
1 answer:
Pachacha [2.7K]3 years ago
7 0
(-5)/3 - 6/(-5)
You can solve it now :)
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A 1-kg mass at the earth's surface weighs about? a. 1 n. b. 5 n. c. 10 n. d. 12 n. e. none of these
ValentinkaMS [17]

A 1-kg mass at the earth's surface weighs about C. 10N

The third planet from the Sun is the Earth. It is the seventh largest in terms of size and weighs roughly 5.98 1024 kg. The inherent quality of mass is unaffected by the environment of the object or the technique employed to quantify it.

Newton's law of gravitation can be used to estimate the mass of the Earth. This is set to the fundamental formula, which reads: force (F) = mass (m) times acceleration. Gravitational acceleration (G) is equal to 9.8 m/s2, the Earth's radius is 6.37 106 m, and the gravitational constant (G) is 6.673 1011 Nm2/kg2. The Earth has a mass of 5.96 1024 kg after rearranging the equation and entering all the numbers.

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3 0
1 year ago
Help!!!!!!!!!!!!!!!!!!! I need someone to check my homework, I will give you 50 points if you answer!!!
bogdanovich [222]
I might be incorrect but I’m pretty confident that all of it is right. I think you’re good.
6 0
4 years ago
Light can travel through a medium, but it does not require a medium.<br> a. True<br> b. False
kaheart [24]

That's true.  Light can travel through glass, water or jello,
but it also gets here very effectively through empty space,
from the sun and stars.

6 0
3 years ago
HELP WITH SCIENCE! (the first are part of the same question)
klio [65]
A Mechanical wave is a wave the does require a medium to transfer.
7 0
4 years ago
By what factor would your weight increase if you could stand on the sun? (never mind that you can't.)
Fofino [41]

Gravity on the surface of sun is given as

g = \frac{GM}{R^2}

here we know that

M = 1.98 \times 10^{30} kg

R = 6.95 \times 10^8 m

now we will have

g = \frac{(6.67 \times 10^{-11})(1.98 \times 10^30)}{(6.95 \times 10^8)^2}

g = 273.4 m/s^2

now we need to find the ratio of weight on surface of sun and on surface of Earth

R = \frac{mg_{sun}}{mg_{earth}}

R = \frac{273.4}{9.8} = 28 times

so weight will increase by 28 times

6 0
3 years ago
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