Answer:They decided to count 10000 muons because of classical predictions. When you count 1000 initial muons.they would expect only 1.5 muons
Explanation:
t= 4205/0.98 = 1.43×10^-5sec
Classically,number of surviving muons= No exp(-0.693t/t)
N=10^4exp[(-0.694×(1.43×10^-5)/1.52×10-6)]
N= 14.7=15
Relativistic time t'=t/y
t'=(1.43×10^-5)×sqrt(1-(0.98c)^2/c^2
t'=2.84×10^-6secs
N= 10^4exp[(-0.693×(3.84×10^-6)/1.52×10^-6]
N relativistic=2739
Answer:
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Answer: make objective observations.
Explanation:
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