Answer:
The answer to your question is:
a) 2.5 mol of Fe
b) 5.63 mol of H2
c) 672 g of Fe2O3
Explanation:
a) Fe₂O₃(s) + 3H₂(g) → 2Fe + 3H₂O(l)
1 mol of Fe₂O₃ ------------- 2 mol of Fe
1.25 mol ------------- x
x = (1.25 x 2) / 1
x = 2.5 mol of Fe
b) Fe₂O₃(s) + 3H₂(g) → 2Fe + 3H₂O(l)
3 moles of H2 ---------------- 2 moles of Fe
x ---------------- 3.75 mol Fe
x = (3.75 x 3) / 2
x = 5.63 mol of H2
c) Fe₂O₃(s) + 3H₂(g) → 2Fe + 3H₂O(l)
1 mol of Fe2O3 ------------------ 3 moles of H2O
x ---------------- 12.5 moles of H2O
x = (12.5 x 1) / 3
x = 4.2 moles of Fe2O3
MW Fe2O3 = (2 x 56) + (16 x 3)
= 112 + 48
= 160 g
160 g Fe2O3 ----------------- 1 mol of Fe2O3
x ----------------- 4.2 moles of Fe2O3
x = (4.2 x 160) / 1
x = 672 g of Fe2O3