<span>For this reaction, oxidation number of Carbon in
CO would be +2 while oxidation number of carbon in CO2 would be +4 and so this
means that carbon has oxidized. Oxidation number of nitrogen in NO is +2. While
oxidation number of nitrogen in N2 is 0 so this means that nitrogen had reduced.
The reducing agent is the one which provides electrons by oxidizing itself so
in this case; CO is the reducing agent while the C in CO oxidized to produce
electrons. </span><span>I
am hoping that this answer has satisfied your query about and it will be able
to help you, and if you’d like, feel free to ask another question.</span>
This one is beta decay (the -1 subscript tells us that)
Thallium has got 81 protons
<u>Have a nice days.......</u>
#1
- See H and C have shared their electrons so it's Covalent bonding
#2
Yes here we can see the dots and crosses clearly.
#3
It's Methane or CH_4
#4
There is no double bond
