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MrRissso [65]
4 years ago
13

Plants are capable of using nitrogen directly from the atmosphere. True false

Chemistry
1 answer:
Nataly_w [17]4 years ago
5 0
True I believe because plants require gases which they take from the air.
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Please help ! its urgent!!
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D

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Respiration is the process by which you get energy from food. So energy in food is converted to a form that can be used by the body

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3 years ago
Round to four significant figures 0.00238866
mixas84 [53]
0.0024 Is it rounded to four significant figures
6 0
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What is the hybridization of the central atom in becl2?
Anuta_ua [19.1K]
Its hybridization would be sp because Be only has 2 covalent bonds with Cl
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What 3 mixtures can be separated by filteration
grandymaker [24]
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7 0
4 years ago
Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
4 years ago
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