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scZoUnD [109]
3 years ago
6

Which formula id correctly paired with its name? A. MgSO↓ = magnesium chlorine

Chemistry
1 answer:
Nostrana [21]3 years ago
4 0
D. CuCl2 copper(2)chloride 
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Suppose 13L of gas is known to contain .965 Mol. If the amount of gas is Increased to 3.20 mol, what new volume will result? (Av
Ostrovityanka [42]

Answer &Explanation:

From Avogadro's lawa equal volume of gas contain equal number of moles

V=N

Hence

13L=965

XL=3.2mol

Hint:as the question state is increase to iteans final mol was 3.2 but if it could state by it would mean initial moles plus adde moles ie 3.2mol)

Cross multiplication

The new volume will be

=(3.2mol×13L÷965mol)

=0.043L

8 0
3 years ago
Ethyl acetate can be prepared by an SN2 reaction. Draw the alkylbromide and nucleophile used in the reaction. Remember to includ
bulgar [2K]

Answer:

Few important points related to S_N2 reaction:

1. S_N2 is a one-step reaction that follows second order kinetics.

2. In S_N2 reaction, a transition state is formed in situ.

3. Strong nucleophiles like OH^- \ or\  CN^- are used in case of bi-molecular nucleophilic substitution reaction.

Ethyl acetate can be prepared by a second-order nucleophilic substitution reaction between acetic acid and ethyl bromide.  

The reaction between acetic acid and ethyl bromide is drawn below:

8 0
3 years ago
Read 2 more answers
What takes place in organelles called chloroplasts
Vitek1552 [10]
Photosynthesis takes place in the chloroplasts, that is why the chloroplasts is green. The function of this organelles is to create energy into sugar from the sunlight.
5 0
3 years ago
1. How many moles are contained in 2.22 x 1024 molecules of calcium fluoride?
Black_prince [1.1K]

Answer:

= 3.7moles

Explanation:

I mole = 6.022 × 10²³ molecules

I molecule = 1 ➗ 6.022 × 10²³ moles

2.22 ×10‘’ 24molecules  = (2.22×10‘’ 24) ÷6.022 × 10²³ moles

Number of moles = 2.22/6.022 × 10" 24-23

Number of moles = 0.37 × 10

Number of moles = 3.7moles

I hope this was helpful, please mark as brainliest

3 0
3 years ago
In an experiment, 12.0dm3 of oxygen, measured under room conditions, is used to burn completely 0.10mol of propan-1-ol. What is
Ksju [112]
2C₃H₇OH + 9O₂ = 6CO₂ + 8H₂O

V(O₂)=12.0 dm³
n(C₃H₇OH)=0.1 mol

n(O₂)=12.0 dm³/22.4 dm³/mol=0.5357 mol

C₃H₇OH : O₂   2:9    1:4.5

0.1:0.5357
oxygen in excess

V(CO₂)=3Vm*n(C₃H₇OH)

V(CO₂)=3*22.4*0.1=6.72 dm³

5 0
3 years ago
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