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Harlamova29_29 [7]
3 years ago
7

If a gas is moved from a large container to a small container but its temperature and number of moles remain the same, what woul

d happen to the pressure of the gas?
Chemistry
2 answers:
Delvig [45]3 years ago
5 0
Compress and explode.
Ksenya-84 [330]3 years ago
5 0

Explanation:

According to ideal gas law, product of pressure and volume equals the product of number of moles, gas constant and temperature.

Mathematically,     PV = nRT

Therefore, it can be seen that volume is inversely proportional to pressure. So, when gas is moved from a large container to a small container then it means volume of container is reduced.

Hence, pressure on the gas will increase and this will tend to compress the gas.

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<span>Physical change, heat caused this.

Water molecules that only vibrate are in solid form. If heat energy is added, the molecules will speed up their vibrations until they can break loose from the organized pattern of a solid and begin to slide over each other, changing to liquid state. If more heat energy is added, the molecules will speed up more and move randomly in all directions as a gas/vapor. Removing heat energy will reverse these changes.

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4 0
4 years ago
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The heat of vaporization of water is one of the highest know. True/or false
ahrayia [7]

This would be false. Water is a liquid at room temperature... The hottest vaporization temperature would be something that is solid at room temperature.

3 0
4 years ago
Can you give me answers about protons and neutrons and electrons and atoms
seropon [69]

Answer:

I hope this helps...

Explanation:

Generally Speaking...

Atoms are basically LEGO blocks of matter that are composed of protons, neutrons, and electrons.

Both protons and neutrons are located in the nucleus of an atom. As protons are are positivley charged and neutrons simlply have no charge, the identity (atomic number) of an element is characterized by the quantity of protons located in the nucleus.

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5 0
3 years ago
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igor_vitrenko [27]

Answer:

Positive interdependence.

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8 0
3 years ago
when 878 J of heat is added to 5 grams of oil at 34˚C , the temperature increases to 56˚C. Wha tis the specific heat of the oil?
sveta [45]

The answer for the following problem is explained below.

<u>The specific heat of oil is 7.98 J/gram °C</u>

Explanation:

Given:

heat (q)=878 J

mass of oil (m) =5 grams

initial temperature (t_{1}) =34°C

final temperature (t_{2}) = 56°C

To solve:

specific heat of the oil (c)

We know;

<u><em>c =q÷(mΔT)</em></u>

ΔT= (t_{2}) - (t_{1})

ΔT =  56°C - 34°C

ΔT = 22°C

c =\\ \frac{878}{5*22}

c =878÷ 110

<u>c =7.98 J/gram °C</u>

<u>Therefore the specific heat of oil is 7.98 J/gram °C</u>

6 0
3 years ago
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