Can you give a little more info :)
Balanced reaction: A(g) + 2B(g) ⇄ 4C(g) + D(g).
Kp = [C]⁴·[D] / [A]·[B]².
<span>[A] - equilibrium concentration of reactant A.
</span>[B] - equilibrium concentration of reactant B
[C] - equilibrium concentration of product C.
[D] - equilibrium concentration of product D.
The substances on the right side of the reaction are written at the top of the Kp<span> expression and those on the left at the bottom.</span>
Answer:
50 mL of HCl is required to react completely with 2.50g of sodium hydrogen carbonate.
Explanation:
The balanced equation shows that 1 mol of NaHCO₃ reacts with 1 mol of HCl. Therefore, we need to calculate the amount of moles present in 2.50g of NaHCO₃ to know how much in moles we will need of HCl. Then, we need to use the concentration to calculate the volume of the HCl solution that will be required.
First step: Calculating the number of moles of NaHCO₃
MM NaHCO₃ = 84.0 g/mol, m = 2.50 g
Second step: Calculating the volume of HCl
It’s called an ion . An atom that loses electron is called an ion
Answer:
To make a 3.50 M solution, 38.5 moles of solute will be needed if 11 liters of solution are required.
Explanation:
Molarity is defined as a concentration unit that indicates the number of moles of solute per liter of solution. That is, it indicates the number of moles of solute that are dissolved in a given volume. Then, the molarity is calculated by dividing the moles of the solute by the liters (volume) of the solution:
Molarity is expressed in units ().
So, knowing the definition of molarity, you can apply a rule of three as follows: if by the definition of molarity in 1 L of solution there are 3.5 moles of solute, in 11 L of solution how many moles of solute are there?
moles=38.5
<u><em>To make a 3.50 M solution, 38.5 moles of solute will be needed if 11 liters of solution are required.</em></u>
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