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Kisachek [45]
3 years ago
12

Why is soft iron used for the core of an electromagnet?

Physics
2 answers:
aliina [53]3 years ago
5 0

Answer:

Because of the high permeability and high saturation level of holding magnetism.

Explanation:

Soft iron always used in the core of an electromagnet because of the following reason which are discussed below.

  • Permeability: These magnets are highly permeable means they can gain magnetism when current is passes through them and instantly loose magnetism after removal of current.
  • High saturation level: The property of these soft magnets are they have the high value of saturation means they can hold high level of magnetism without easily saturating.
Tanzania [10]3 years ago
3 0
The soft iron<span> inside the coil makes the magnetic field stronger because it becomes a magnet itself when the current is flowing. </span>Soft iron<span> is </span>used<span> because it loses its magne</span>
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When the displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position, what fraction of the
KonstantinChe [14]

Answer:

The ratio is  KE : TM  =  0.75

Explanation:

from the question we are told that

  The displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position

Generally the total mechanical  energy of the mass is mathematically represented as

        TM  =  \frac{1}{2}  *  k  *  A^2

Here  k is the spring constant  ,  A is the total displacement of the  the mass  from maximum  compression to maximum extension of the spring

Generally this total mechanical energy is mathematically represented as

        TM  =  KE  + PE

=>     KE = TM  - PE

Here the potential  energy of the mass is mathematically represented as

     PE   = \frac{1}{ 2}  *  k *  [ x ]^2

Here x is the displacement of the mass from maximum compression or extension of the spring to equilibrium position and the value is  

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So

     PE   = \frac{1}{ 2}  *  k *  [ \frac{A}{2}  ]^2

So

      KE =  \frac{1}{2}  *  k  *  A^2 - \frac{1}{2}  *  k  *  [\frac{A}{2} ]^2

=>    KE =  \frac{1}{2}  *  k  *  A^2 - \frac{1}{8}  *  k  *  A ^2

=>    KE =  0.375  *  k  *  A^2

So the ratio of  KE :  TM is  mathematically represented as

       \frac{KE}{TM} =  \frac{0.375  k A^2 }{0.5 k A^2}

=>    \frac{KE}{TM} = 0.75

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