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defon
3 years ago
14

Rank in increasing polarity the carbon-nitrogen single, double, and triple bonds. not enough information to compare. triple <

double < single all have the same polarity. single < double < triple
Chemistry
1 answer:
Tcecarenko [31]3 years ago
8 0
I will rewrite this question so the options are presented more clearly:

Rank in increasing polarity the carbon-nitrogen single, double and triple bonds.

a) not enough information to compare
b) triple < double < single
c) all have the same polarity
d) single < double < triple

The answer we are looking for is b) triple < double < single.

We determine bond polarity by comparing the electronegativities of the two atoms involved in the bond, in this case carbon-nitrogen. Nitrogen is more electronegative than carbon, with electronegativities of 3.04 and 2.55, respectively. You may expect that the electronegativities of the atoms remains the same in each bond, but this is not the case.

In the case of a C-N single bond, the carbon atom is sp³ hybridized. In a C=N double bond, the carbon is sp² hybridized. The more s-character an atom has leads to an increase in the electronegativity of the atom since s-orbitals hold the electrons much tighter. By increasing the s-character of the carbon atom from sp³ to sp², we are increasing the electronegativity which leads to a decrease in the difference in electronegativities between carbon and nitrogen. Therefore, a C-N single bond is more polar than a C=N double bond. This trend continues with a C≡N as the carbon now is sp hybridized with even more s-character and becomes more electronegative still, thus decreasing the polarity further.
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Shtirlitz [24]

Answer: Option (5) is the correct answer.

Explanation:

It is known that the ground state electronic configuration of silicon is [Ne]3s^{2}3p^{2}.

And, we know that when an atom tends to gain an electron then it acquires a negative charge and when an atom tends to lose an electron then it acquires a positive charge.

As Si^{4+} has a +4 charge which means that it has lost 4 electrons. Hence, the electronic configuration of Si^{4+} is 1s^{2}2s^{2}2p^{6}.

According to the Aufbau principle, in the ground state of an atom or ion the electrons fill atomic orbitals of the lowest energy levels first, before filling the higher energy levels.

As 2p orbital is filled after the filling of 2s orbital.

Therefore, we can conclude that 2p orbital will be occupied by the electrons of highest energy for the Si^{4+} ground-state ion.

4 0
3 years ago
A solution contains 0.115 mol h2o and an unknown number of moles of nacl. the vapor pressure of the solution at 30°c is 25.7 tor
Valentin [98]
According to Raoult's low:
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∴ mole fraction of solvent = Vp(Solu) / Vp (Solv)
when we have Vp(solu) = 25.7 torr & Vp(solv) = 31.8 torr 
So by substitution:
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mole fraction of solvent = moles of solvent / (moles of solvent + moles of solute)
by substitute:
∴ 0.808 = 0.115 / (0.115 + X)
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3 years ago
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2 years ago
If a car is traveling 100 km/h and comes to a stop in 3 minutes,what is acceleration of a passenger who is using vehicle restrai
Rama09 [41]

We are given –

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Here–

\qquad\pink{\bf \longrightarrow  Initial\:  velocity =  100 \:km/hr}

\qquad\sf \longrightarrow  Initial\:  velocity = \dfrac{ 100 \times 1000}{3600} \:m/s

\qquad\pink{ \bf \longrightarrow  Initial\:  velocity = 27.78\: m/s}

Now –

\qquad____________________________

\qquad\purple{\bf \longrightarrow  Acceleration  = \dfrac{Final\: Velocity -Initial  \:Velocity }{Time}}

\qquad\purple{\bf \longrightarrow  Acceleration  = \dfrac{v -u}{t}}

\qquad\sf \longrightarrow  Acceleration = \dfrac{(0- 27.78)}{1800}

\qquad\sf \longrightarrow  Acceleration =\cancel{ \dfrac{- 27.78}{1800}}

\qquad\purple{\bf \longrightarrow  Acceleration = -0.15 \: m/s^2}

\qquad_______________________________

6 0
2 years ago
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