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gayaneshka [121]
3 years ago
11

The length of one side of a square is x-5. what is the area of the square

Mathematics
2 answers:
azamat3 years ago
7 0

Step-by-step explanation:

The area of a square can be represented by the following equation:

A = s^{2}

where s is the side length of the square.

We know that the side length is x - 5, so we can plug this into the equation to get the area:

A = s^{2}

A = (x - 5)^{2}

A = x^{2} - 10x + 25

Whitepunk [10]3 years ago
7 0

Answer:

(x-5)(x-5)

X^2-5x-5x+25

x^2-10x+25

Step-by-step explanation:

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2 years ago
An element with mass 430 grams decays by 27.4% per minute. How much of the element is remaining after 19 minutes, to the nearest
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3 years ago
Two similar cylinders have a scale factor of (1.6/3). Find the ratio of their volumes.
Tanzania [10]
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3 0
3 years ago
Read 2 more answers
Two people start from the same point. One walks east at 4 mi/h and the other walks northeast at 8 mi/h. How fast is the distance
kvasek [131]

Answer:

5.89 mi/h

Step-by-step explanation:

This problem can be solved by using different methods. I will use vectors since it's the simplest way in which we can solve it. This can be solved by using related rates of change though.

First, we start by drawing a diagram with the velocity vectors.

A= velocity of the first person

B= velocity of the second person

C= velocity in which they are moving away from each other.

Since there is no acceleration in the problem, we can suppose we are talking about constant speeds, so the velocity at which they are moving away from each other will always remain constant. (It doesn't matter what time it is, the velocity will always be the same)

Having said this we can solve this problem by using the components, by using law of cosines or graphically. I will use law of cosines. The idea is to find the length of side c.

Law of cosines:

C^{2}=A^{2}+B^{2}-2ABcos \gamma

so we can solve the formula for C so we get:

C=\sqrt{A^{2}+B^{2}-2ABcos \gamma}

and now we can substitute the values we know:

C=\sqrt{(4)^{2}+(8)^{2}-2(4)(8)cos 45^{o}}

C=\sqrt{16+64-32\sqrt{2}}

C=\sqrt{80-32\sqrt{2}} mph

if we want an exact answer, then that will be the exact answer, which approximates to:

C=5.89 mph

4 0
3 years ago
A<br> Find tan a.<br> r<br> √5,-√7)<br> ✓[?<br> Enter
Virty [35]

Answer:

tan(\alpha)=-\frac{\sqrt{35}}{5}

Step-by-step explanation:

Tan can be defined as: \frac{sin(\theta)}{cos(\theta)} as it simplifies to opposite/adjacent. If you know a bit about the unit circle, you'll know that the x-coordinate is going to be cos(theta) and the y-coordinate is going to be sin(theta). Since the sin(theta) is defined as opposite/hypotenuse, and the hypotenuse = 1, so sin(theta) is defined as the opposite side, which is the y-axis. Same thing goes for cos(theta), except the adjacent side is the x-axis.

Using this we can define tan

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8 0
2 years ago
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