Calculate the speed of a plane which travels a distance of 2100 miles in 3 hours

You are on a cruise ship traveling north at a speed of 13 m/s with respect to land. 1) if you walk north toward the front of the

Brrunno [24]

In order to find the our own velocity with respect to land,we need to apply the theory of relative velocity.

Now consider the velocity of the ship traveling towards the north with respect to land as A.Consider our own velocity headed northwards as B.

The relative velocity is the velocity that the body A would appear to an observer on the body B and vice versa.

In this case the relative velocity would be arrived by summing up our velocity with the velocity of the ship as the object (I) is travelling in the ship.

Relative velocity = Velocity of Body A+ Velocity of Body B.

Velocity of the ship traveling towards the north with respect to land(A)= 13.0m/s. (Given)

Our own velocity headed northwards(B)= 2.8 m/s.

Relative velocity = Velocity of Body A+ Velocity of Body B.

Relative velocity= 13.0 + 2.8 = 15.8m/s.

Thus our own velocity with respect to the land is 15.8 m/s.

5 0

3 years ago

The electron gun in a television tube accelerates electrons (mass = 9.11x10^-31 kg, charge = 1.6 x 10^-19C) from rest to 3 x10^7

stich3 [128]

Answer:

Electric field acting on the electron is 127500 N/C.

Explanation:

It is given that,

Mass of an electron, $m=9.11\times 10^{-31}\ kg$

Charge on electron, $q=1.6\times 10^{-19}\ C$

Initial speed of electron, u = 0

Final speed of electron, $v=3\times 10^7\ m/s$

Distance covered, s = 2 cm = 0.02 m

We need to find the electric field required. Firstly, we will find the acceleration of the electron from third equation of motion as :

$a=\dfrac{v^2-u^2}{2s}$

$a=\dfrac{(3\times 10^7)^2-0}{2\times 0.02}$

$a=2.25\times 10^{16}\ m/s^2$

According to Newton's law, force acting on the electron is given by :

F = ma

$F=9.1\times 10^{-31}\times 2.25\times 10^{16}$

$F=2.04\times 10^{-14}\ N$

Electric force is given by :

F = q E, E = electric field

$E=\dfrac{F}{q}$

$E=\dfrac{2.04\times 10^{-14}}{1.6\times 10^{-19}}$

E = 127500 N/C

So, the electric field is 127500 N/C. Hence, this is the required solution.

8 0

3 years ago

A student measures the speed of yellow light in water to be 2.00x10^8

max2010maxim [7]

NOTE: The given question is incomplete.

The complete question is given below.

A student measures the speed of yellow light in water to be 2.00 x 10⁸ m/s. Calculate the speed of light in air.

Solution:

Speed of yellow light in water (v) = 2.00 x 10⁸ m/s

Refractive Index of water with respect to air (μ) = 4/3

Refractive Index = Speed of yellow light in air / Speed of yellow light in water

Or, The speed of yellow light in air = Refractive Index × Speed of yellow light in water

or, = (4/3) × 2.00 x 10⁸ m/s

or, = 2.67 × 10⁸ m/s ≈ 3.0 × 10⁸ m/s

Hence, the required speed of yellow light in the air will be 3.0 × 10⁸ m/s.

7 0

2 years ago

Study the analogy, and then answer the question that follows.

nordsb [41]

What kind of analogy is this?
A. synonyms
B. part to whole
C. degrees of intensity
D. cause to effect
This is because a synonym refers to things like "normal" or "regular" like your calling someone something.

6 0

3 years ago

Read 2 more answers

What best describes the volcanic process of magma with dissolved water vapor and other gases as it nears the Earth surface?

Assoli18 [71]

Answer:

Pressure on the molten rock lessens and the gases dissolved in rock can bubble and expand rapidly causing violent eruptions.

Explanation:

that's just how it works lol. hope this helps :]

6 0

2 years ago