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Oliga [24]
3 years ago
15

2-8-6 refers to the proton configuration for sulfur. True Or False

Chemistry
2 answers:
olganol [36]3 years ago
6 0

Answer: its true

Explanation:

Sergio039 [100]3 years ago
4 0

Answer:

The answer is true I believe

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What is the work required for the separation of air (21-mol-% oxygen and 79-mol-% nitrogen) at 25°C and 1 bar in a steady-flow p
Ronch [10]

Answer:

4oo

Explanation:

it

4 0
3 years ago
One hundred million copper atoms are arranged in a line. Which is a reasonable estimate for the length of this line?
Anettt [7]
The size of an atom is roughly 10^-10 metres

10^-10 • 100,000,000 = 0.01 metres

Since 1 metre = 100 centimetre

0.01 x 100 = 1 centimetre

There’s your answer
8 0
3 years ago
White light, which consists of all frequencies, forms which type of spectrum?
malfutka [58]
Visible light spectrum.

The visible light spectrum is part of the electromagnetic radiation spectrum
5 0
3 years ago
Nitrogen and oxygen do not react appreciably at room temperature, as illustrated by our atmosphere. But at high temperatures, th
Gre4nikov [31]

Answer : The equilibrium concentration of NO is, 0.0092 M.

Solution :

First we have to calculate the concentration of NO.

\text{Concentration of NO}=\frac{\text{Moles of }NO}{\text{Volume of solution}}=\frac{0.3152mol}{2.0L}=0.1576M

The given equilibrium reaction is,

                           N_2(g)+O_2(g)\rightleftharpoons 2NO(g)

Initially conc.      0        0           0.1576

At eqm.               (x)       (x)        (0.1576-2x)

The expression of K_c will be,

K_c=\frac{[NO]^2}{[N_2][O_2]}

0.0153=\frac{(0.1576-2x)^2}{(x)\times (x)}

By solving the term, we get:

x=0.0742,0.0839

Neglecting the 0.0839 value of x because it can not be more than initial value.

Thus, the value of 'x' will be, 0.0742 M

Now we have to calculate the equilibrium concentration of NO.

Equilibrium concentration of NO = (0.1576-2x) = [0.1576-2(0.0742)] = 0.0092 M

Therefore, the equilibrium concentration of NO is, 0.0092 M.

5 0
3 years ago
An object has a mass of 4 grams and a volume of 2 cm^3.what is the density of the object?
stellarik [79]

Answer:

2.0 grams per cubic centimeter

Explanation:

(You can refer to the DMV triangle to help you solve this!)

Density = Mass/Volume

Density = 4.0g/2.0cm3

Density = 2.0g/cm3

Hope this helps!!!

-Unicorns110504

*Please mark brainliest*

3 0
3 years ago
Read 2 more answers
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