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3 years ago

5. Express the number 1.36 x 104 in common decimal form.

Chemistry

1 answer:

zysi [14]3 years ago

5 0

Answer: D

Explanation: You move the decimal back 4 times.

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Sulfur undergoes combustion to yield sulfur trioxide by the following reaction equation:

12345 [234]

Answer:

Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J

Explanation:

Given reaction: 2S + 3O₂ → 2 SO₃

Given: The enthalpy of reaction: ΔH = - 792 kJ

Given mass of S: w₂ = 42.8 g, Molar mass of S: m = 32 g/mol

In the given reaction, the number of moles of S reacting: n = 2

As, Number of moles: $n = \frac{mass\: (w_{1})}{molar\: mass\: (m)}$

∴ mass of S in 2 moles of S: $w_{1} = n \times m = 2\: mol \times 32\: g/mol = 64\: g$

Given reaction: 2S + 3O₂ → 2 SO₃

In this reaction, the limiting reagent is S

⇒ 2 moles S produces (- 792 kJ) heat.

or, 64 g of S produces (- 792 kJ) heat.

∴ 42.8 g of S produces (x) amount of heat

⇒ The amount of heat produced by 42.8 g S:

$x = \frac{(- 792\: kJ) \times 42.8\: g}{64\: g} = (-529.65)\: kJ$

$\Rightarrow x = (-5.2965 \times 10^{2})\: kJ = (-5.2965 \times 10^{5})\: J$

$(\because 1 kJ = 10^{3} J)$

Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J

8 0

3 years ago

Several properties of water are shown. Classify each property as a physical property or a chemical property.

34kurt

Chemical property:

Can be split into hydrogen and oxygen
Reacts with certain metals

Physical property:

Is liquid at room temperature
Has a density of 1.0 g/cm³

7 0

2 years ago

In the formula for water ,(H2O), what does the lack of subscript after the O indicate?

ladessa [460]

I believe its B. The chemical formula for water H2O represents 2 hydrogen and 1 oxygen in the compound.

4 0

2 years ago

Read 2 more answers

Under the same conditions of solar radiation, compared with oceans the land will warm__________ !Please help!

Katarina [22]

Land will warm faster

8 0

3 years ago

The combustion of 1 mole of CO according to the reaction CO(g) + ½O2(g) → CO2(g) + 67.6 kcal gives off how much heat?

Tomtit [17]

When the enthalpy value is given, we can calculate how much heat is use or produces in a given equation.

67.6 kCal ---> 67.6 kCal= 1 mol of reaction
1 mol of reaction= 1 mol of CO (based on the coefficient)

so 1 mole of CO gives us 67.6 kCal of heat.

calculation:

1 mol CO $\frac{67.5 kcal}{1 mol CO} = 67.5 kcal$

5 0

2 years ago