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dezoksy [38]
3 years ago
7

5. Express the number 1.36 x 104 in common decimal form.

Chemistry
1 answer:
zysi [14]3 years ago
5 0

Answer: D

Explanation: You move the decimal back 4 times.

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Sulfur undergoes combustion to yield sulfur trioxide by the following reaction equation:
12345 [234]

Answer:

Therefore, the amount of heat produced by the reaction of 42.8 g S = <u>(-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J</u>

Explanation:

Given reaction: 2S + 3O₂ → 2 SO₃

Given: The enthalpy of reaction: ΔH = - 792 kJ

Given mass of S: w₂ = 42.8 g, Molar mass of S: m = 32 g/mol

In the given reaction, the number of moles of S reacting: n = 2

As, Number of moles: n = \frac{mass\: (w_{1})}{molar\: mass\: (m)}

∴  mass of S in 2 moles of S: w_{1} = n \times m = 2\: mol \times 32\: g/mol = 64\: g

<em>Given reaction</em>: 2S + 3O₂ → 2 SO₃

<em>In this reaction, the limiting reagent is S</em>

⇒ 2 moles S produces (- 792 kJ) heat.

or, 64 g of S produces (- 792 kJ) heat.

∴ 42.8 g of S produces (x) amount of heat

⇒ <u><em>The amount of heat produced by 42.8 g S:</em></u>

x = \frac{(- 792\: kJ) \times 42.8\: g}{64\: g} = (-529.65)\: kJ

\Rightarrow x = (-5.2965 \times 10^{2})\: kJ = (-5.2965 \times 10^{5})\: J

(\because 1 kJ = 10^{3} J)

<u>Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J</u>

8 0
3 years ago
Several properties of water are shown. Classify each property as a physical property or a chemical property.
34kurt

Chemical property:

  • Can be split into hydrogen and oxygen
  • Reacts with certain metals

Physical property:

  • Is liquid at room temperature
  • Has a density of 1.0 g/cm³
7 0
2 years ago
In the formula for water ,(H2O), what does the lack of subscript after the O indicate?
ladessa [460]
I believe its B. <span>The chemical formula for water H2O represents 2 hydrogen and 1 oxygen in the compound.  </span>
4 0
2 years ago
Read 2 more answers
Under the same conditions of solar radiation, compared with oceans the land will warm__________ !Please help!
Katarina [22]
Land will warm faster 
8 0
3 years ago
The combustion of 1 mole of CO according to the reaction CO(g) + ½O2(g) → CO2(g) + 67.6 kcal gives off how much heat?
Tomtit [17]
When the enthalpy value is given, we can calculate how much heat is use or produces in a given equation. 

67.6 kCal ---> 67.6 kCal= 1 mol of reaction
1 mol of reaction=  1 mol of CO (based on the coefficient)

so 1 mole of CO gives us 67.6 kCal of heat.

calculation:

1 mol CO\frac{67.5 kcal}{1 mol CO} = 67.5 kcal




5 0
2 years ago
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