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defon
3 years ago
15

Substances like krypton, which is a gas at room temperature and pressure, can often be liquified or solidified only at very low

temperatures. At a pressure of 1 atm, does not condense to a liquid until –153.2°C and does not freeze until –157.1°C. What are the equivalent absolute temperatures?
Chemistry
1 answer:
inysia [295]3 years ago
8 0

Answer:

The boiling and freezing temperatures of krypton at absolute scale are 119.95 K and 116.05 K, respectively.

Explanation:

The absolute temperature on SI units corresponds to Kelvin scale, whose conversion formula in terms of the Celsius scale is:

T_{K} = T_{C} + 273.15

Where:

T_{K} - Absolute temperature, measured in Kelvins.

T_{C} - Relative temperature, measured in Celsius.

Finally, freezing and boiling temperatures are converted into absolute scale:

Boiling temperature

T_{K} = (-153.2 + 273.15)\,K

T_{K} = 119.95\,K

Freezing temperature

T_{K} = (-157.1 + 273.15)\,K

T_{K} = 116.05\,K

The boiling and freezing temperatures of krypton at absolute scale are 119.95 K and 116.05 K, respectively.

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Equation: MgOH2 (s) --> MgO (s) + H2O (g)

And it's already balanced.

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3 0
3 years ago
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PLS HELP What is the mass of hydrogen atoms that is measured at 54 u?
tankabanditka [31]

The mass of hydrogen atoms that is measured at 54 u given the relationship is 89.64×10¯²⁴ g

<h3>Conversion scale </h3>

1 u = 1.66×10¯²⁴ g

<h3>How to determine the mass of hydrogen atoms </h3>
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1 u = 1.66×10¯²⁴ g

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54 u = 54 × 1.66×10¯²⁴ g

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Thus, the mass of the hydrogen atoms measured at 54 u is 89.64×10¯²⁴ g

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3 0
2 years ago
5. Water is known to have a composition which is 88.8% oxygen by mass. If you had a
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Oxygen : 367*0.888=325.896
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4 0
3 years ago
Given the following data: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) ΔH = −23 kJ 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ΔH = −39
nalin [4]

Answer:

ΔH° = -11 kj

Explanation:

Step 1: Data given

1)   Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g)    ΔH = −23 kJ

2)   3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g)   ΔH = −39 kJ

3)   Fe3O4(s) + CO(g) → 3 FeO(s) + CO2(g) ΔH = +18 kJ

Step 2: The balanced equation

FeO + CO → Fe + CO2

Step 3:  Calculate ΔH for the reaction FeO(s) + CO(g) → Fe(s) + CO2(g).

To get this equation, we need to combine the 3 equations

We have to multiply the third equation by 2.

2Fe3O4(s) + 2CO(g) → 6 FeO(s) + 2CO2(g) ΔH = +54 kJ

<u>This equation we add to the second equation</u>

3Fe2O3(s) + CO(g) + 2Fe3O4(s) + 2CO(g) → 2Fe3O4(s) + CO2(g) + 6FeO(s) + 2CO2 (g)

3Fe2O3(s) + 3CO(g) →  3CO2(g) + 6FeO(s)

ΔH°  = 2*18 + (-39) = 36 - 39 =  -3 kJ

<u>This new equation we will divide by 3 </u>

3Fe2O3(s) + 3CO(g) →  3CO2(g) + 6FeO(s)

Fe2O3(s) + CO(g) →  CO2(g) + 2FeO(s)

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<u>Now we will substract this new equation from the first equation</u>

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2CO(g)  + 2FeO(s)  → 2Fe(s) + 2CO2(g)

ΔH° = -23kJ +1kJ

ΔH° = -22 kj

<u>The next equation we will divide by 2</u>

2CO(g)  + 2FeO(s)  → 2Fe(s) + 2CO2(g)

CO(g)  + FeO(s)  → Fe(s) + CO2(g)

ΔH° = -22kJ /2

ΔH° = -11 kj

7 0
3 years ago
As one mass increases, what happens to the gravitational force.
Shalnov [3]

Answer:

Gravitational force is directly promotional to the mass

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