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Sav [38]
4 years ago
9

The surface Area of piston A is 2 square inches, while the surface are of piston B is 4 square inches. If piston A is pushed dow

n 6 inches, how far will piston B move up?
Physics
1 answer:
Usimov [2.4K]4 years ago
7 0

Answer:

Distance piston B = 3 [in]

Explanation:

This problem can be solved using the pascal principle, which is applied for both pressures and volumes. In this case we use the definition of volumes, which says that the volume displaced fluid on one side of the Pistons should be equal to the volume displaced on the other side of the piston.

We know that the volume is equal to the product of an area by a length

V_{A}=V_{B}\\A_{A}*d_{A}=A_{B}*d_{B}\\2*6=4*d_{B}\\d_{B}=12/4\\d_{B}=3[in]

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A 100-newton box is placed on a table. The table can exert a maximum normal force of 80 newtons. What will happen to the box?
myrzilka [38]

Answer:

D

Explanation:

Dddddddddddddddddd

8 0
4 years ago
3. A large passenger ship required a force of 1,600,000 N to move 2000 m. How much work is done on the ship?​
Dovator [93]

Answer:

3,200,000,000 J

Explanation:

Work is defined as the amount of energy transferred as an object is moved a certain distance with a certain force. Mathematically, we express this with the equation

W=Fs

where W is work (measured in joules), F is the force applied (in Newtons), and s is the distance, also called the <em>displacement </em>(in meters).

Here, we have F = 1,600,000 N and s = 2000 m, so our work will be

W=1.600.000(2.000)=3.200.000.000 J

7 0
3 years ago
Replacing an object attached to a spring with an object having 14 the original mass will change the frequency of oscillation of
Pachacha [2.7K]

Answer:

<em>The frequency changes by a factor of  0.27.</em>

<em></em>

Explanation:

The frequency of an object with mass m attached to a spring is given as

f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }

where f is the frequency

k is the spring constant of the spring

m is the mass of the substance on the spring.

If the mass of the system is increased by 14 means the new frequency becomes

f_{n} = \frac{1}{2\pi } \sqrt{\frac{k}{14m} }

simplifying, we have

f_{n} = \frac{1}{2\pi \sqrt{14} } \sqrt{\frac{k}{m} }

f_{n} = \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }

if we divide this final frequency by the original frequency, we'll have

==> \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }  ÷  \frac{1}{2\pi } \sqrt{\frac{k}{m} }

==> \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }  x  2\pi \sqrt{\frac{m}{k} }

==> 1/3.742 = <em>0.27</em>

7 0
3 years ago
You want to launch a stone using the elastic band of a slingshot. The force that the elastic band applies to an object is given
Ksenya-84 [330]

Answer:

0.00288 J

Explanation:

We know that

W= Fds

F = −α∆s^4

α = 45 N/m^4 and ∆s = displacement

W= −α∆s^4ds

integrating both the sides from s= 0 to 0.2

W= 45/5×0.2^5= 0.00288 J

3 0
3 years ago
A screen door spring is stretched
bija089 [108]

Answer:

216.39 N/m

Explanation:

F = 64.7 N

x = 0.299 m

Plug those values into Hooke's Law:

F = kx

64.7 N = k(0.299 m)

---> k = 216.39 N/m

8 0
3 years ago
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