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Sav [38]
4 years ago
9

The surface Area of piston A is 2 square inches, while the surface are of piston B is 4 square inches. If piston A is pushed dow

n 6 inches, how far will piston B move up?
Physics
1 answer:
Usimov [2.4K]4 years ago
7 0

Answer:

Distance piston B = 3 [in]

Explanation:

This problem can be solved using the pascal principle, which is applied for both pressures and volumes. In this case we use the definition of volumes, which says that the volume displaced fluid on one side of the Pistons should be equal to the volume displaced on the other side of the piston.

We know that the volume is equal to the product of an area by a length

V_{A}=V_{B}\\A_{A}*d_{A}=A_{B}*d_{B}\\2*6=4*d_{B}\\d_{B}=12/4\\d_{B}=3[in]

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I have four questions.
Inga [223]

Answer:

The potential energy of the ball is 784 joules. And the kinetic energy of it is 392 while falling halfway down.

Explanation:

PE = mass (2kg) * Gravitational acceleration (9.8 m/s^2)* height (40 meters)

KE = 1/2 mass (1 kg) * velocity^2 (19.8)

7 0
4 years ago
Read 2 more answers
Write four (4) strategies on how can we manage land use around South Florida. For each strategy, explain it's benefits to the en
a_sh-v [17]

Answer:

What are some ways we can improve on our land use?

- Avoid deforestation and close the forest frontier.

The first-order priority is to end deforestation by closing the "forest frontier" or intact forests, to development.

- Increase agricultural productivity.

- Restore forests and landscapes.

- Reduce food loss and waste.

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3 0
3 years ago
A roller coaster starts from rest at point A. What is its speed at point C if the track is frictionless.
OleMash [197]
At A, coaster is only associated with potential energy.
At B, coaster is associated with kinetic as well as potential energy.
Since the track is frictionless, no energy will be lost when coaster reaches from point A to point B. Therefore, according to conservation of energy, total energy at A should be equal to total energy at B.
Total energy at A = mgh = mg(12) 
Total energy at B = mgh+ mv²/2 = mg(2) + mv²/2
∴12mg = 2mg + mv²/2
∴(12g-2g)×2 = v²
∴v² = 20g
∴v = 14m/s.

Again conserving energy at points B and C.
Total energy at B = 2mg + m(14)²/2 
Total energy at C = 4mg + mv²/2
∴2mg + m(14²)/2 = 4mg + mv²/2
Solving this you get,
v = 12.52 m/s.
Therefore, speed of roller coaster at point C is 12.52 m/s.
8 0
4 years ago
The total weight of a car with passengers is 30,000N. The area of contact of each of the four tyres with the ground is 0.025m2.
vlabodo [156]

Answer:

<em>The minimum pressure car tire pressure is 300,000 Pa</em>

Explanation:

<u>Pressure</u>

It's a measure of the force exerted by an object per unit surface:

\displaystyle P=\frac{F}{A}

Where F is the force applied on a surface area A.

We are given the total weight of a car with passengers as Ft=30,000 N and we also know the area of contact of each tire with the ground as A=0.025 m^2.

The minimum pressure each tire can have is when the total weight is evenly distributed in all four tires, thus F=Ft/4=7,500 N.

Calculating the pressure:

\displaystyle P=\frac{7,500}{0.025}

P=300,000 Pa

The minimum pressure car tire pressure is 300,000 Pa

7 0
3 years ago
) Calculate current passing in an electrical circuit if you know that the voltage is 8 volts and the resistance is 10 ohms
Svetach [21]

Explanation:

<em>Hey</em><em>,</em><em> </em><em>there</em><em>!</em>

<em>Here</em><em>,</em><em> </em><em>In</em><em> </em><em>question</em><em> </em><em>given</em><em> </em><em>that</em><em>, </em>

<em>potential</em><em> </em><em>difference</em><em> </em><em>(</em><em>V</em><em>)</em><em>=</em><em> </em><em>8</em><em>V</em>

<em>resistance</em><em> </em><em>(</em><em>R</em><em>)</em><em>=</em><em> </em><em>1</em><em>0</em><em> </em><em>ohm</em>

<em>Now</em><em>,</em>

<em>According</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>Ohm's</em><em> </em><em>law</em><em>,</em>

<em>V</em><em>=</em><em> </em><em>R</em><em>×</em><em>I</em><em> </em><em> </em><em> </em><em> </em><em>{</em><em> </em><em>where</em><em> </em><em>I</em><em> </em><em>=</em><em> </em><em>current</em><em>}</em>

<em>or</em><em>,</em><em> </em><em>I</em><em> </em><em>=</em><em> </em><em>V</em><em>/</em><em>R</em>

<em>or</em><em>,</em><em> </em><em>I</em><em> </em><em>=</em><em> </em><em>8</em><em>/</em><em>1</em><em>0</em>

<em>Therefore</em><em>, </em><em> </em><em>current</em><em> </em><em>is</em><em> </em><em>4</em><em>/</em><em>5</em><em> </em><em>A</em><em> </em><em>or</em><em> </em><em>0</em><em>.</em><em>8</em><em> </em><em>A</em><em>.</em>

<em>(</em><em>A</em><em>=</em><em> </em><em>ampere</em><em> </em><em>=</em><em> </em><em>unit</em><em> </em><em>of</em><em> </em><em>current</em><em>)</em><em>.</em>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em> </em>

6 0
4 years ago
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