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3 years ago

In order for rejuvenation to take place in a stream, what must occur first?

1 answer:

7 0

The land over the stream flows must uplift - Rejuvenation is the process by which a stream r<span>enews its activity, erosive power, etc. by the uplift or removal of a barrier in the stream's bed. This lowers the base level of the stream and it so that it can begin its downward erosion again.</span>

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Speakers A and B are vibrating in phase. They are directly facing each other, are 8.2 m apart, and are each playing a 78.0 Hz to

Stels [109]

Answer:6.298,4.1,1.9015

Explanation:

Wavelength= $\frac{velocity of sound }{frequency}$

= $\frac{343}{78}$ =4.397 m

Distance of 3rd speaker from speaker A is x

From B 78-x

Difference between the distances must be a whole number of wavelengths

First

$x-\left ( 8.2-x\right )=4.397$ for 1 st wavelength

2x=8.2+4.397=12.597

x=6.298m

second

For zero wavelength

$x-\left ( 8.2-x\right )=0$

2x=8.2

x=4.1m

Third

$\left ( 8.2-x\right )-x=4.397$

x=1.9015 m

6 0

3 years ago

Students want to investigate the inverse relationship between the pressure and temperature of an ideal gas as predicted by the i

grin007 [14]

Answer:

Option B, Fix the piston in place so the volume of the pas remains constant

Explanation:

As we know

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

The effect on variable due to another variable can be studied by keeping the third variable constant.

Hence, in order the study the variation of temperature with pressure or vice versa, the volume needs to fixed at a certain value.

Hence, option B is correct

7 0

3 years ago

What factors cause changes in the temperature of surface water

Elodia [21]

Answer:

sunlight/solar radiation

4 0

3 years ago

Read 2 more answers

A cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. The lift i

WINSTONCH [101]

Answer:

Total work done = = 29811.60 J

Explanation:

Since the person is being moved upward, the person’s potential and kinetic energy are increasing.

To determine the increase in potential energy, the following equation is used;

∆ PE = m * g * ∆ h

m = 78.0 Kg, g = 9.8 m/s, ∆ h = 13.0 m

∆ PE = 78.0 * 9.8 * 13.0 = 9937.20 J

Increase in kinetic energy is given by the following equation;

∆ KE = ½ * m * (vf² – vi²)

vf = 3.4, vi = 0

∆ KE = ½ * 78.0 * 3.4² = 450.84 J

Total work = 9937.20 + 450.84 = 10388.04 J

(b) He is then lifted at the constant speed of 3.40 m/s

Velocity is constant, therefore, there is no increase in kinetic energy. The only work done is the increase of potential energy

∆ PE = 78.0 * 9.8 * 13.0

∆ PE = 9937.20 J

Since his velocity decreased from 3.40 m/s to 0 m/s, his kinetic energy decreased.

∆ KE = ½ * 78.0 * (0² - 3.4²)

∆ KE = - 450.84 J

∆ PE = 78.0 * 9.8 * 13.0 = 9937.20 J

Total work = 9937.20 - 450.84 = 9486.36 J

Sum of works = 10388.04 + 9937.20 + 9486.36 = 29811.60 J

8 0

3 years ago

In a physics experiment, two equal-mass carts roll towards each other on a level, low-friction track. One cart rolls rightward a

xz_007 [3.2K]

Answer:

The correct answer is option a.

Explanation:

Conservation of momentum :

$m_1u_1+m_2u_2=m_1v_1+m_1v_2$

Where :

$m_1, m_2$ = masses of object collided

$u_1,u_2$ = initial velocity before collision

$v_1,v_2$ = final velocity after collision

We have :

Two equal-mass carts roll towards each other.

$m_1=m_2=M$

Initial velocity of $m_1=u_1=2 m/s$

Initial velocity of $m_2=u_2=-1 m/s$ (opposite direction)

Final velocity of $m_1=v_1=v$ (same direction )

Final velocity of $m_2=v_2=v$ (same direction)

$M\times 2 m/s+M(-1 m/s)=Mv+Mv$

$1 m/s=2v$

v = 0.5 m/s

rg135

The speed of the carts after their collision is 0.5 m/s.

7 0

3 years ago