Apply the general results obtained in the full analysis of motion under the influence of a constant force in Section 2.5 to answ
er the following questions. You hold a small metal ball of mass a height above the floor. You let go, and the ball falls to the floor. Choose the origin of the coordinate system to be on the floor where the ball hits, with up as usual. Express all results in terms of , , and . Just after release, what are and
1 answer:
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Explanation:
A worker picks up the bag of gravel. We need to find the speed of the bucket after it has descended 2.30 m from rest. It is case of conservation of energy. So,
h = 2.3 m
So, the speed of the bucket after it has descended 2.30 m from rest is 6.71 m/s.
Answer:
x = 5.79 m
Explanation:
given,
mass of the car = 39000 Kg
spring constant = 5.7 x 10⁵ N/m
acceleration due to gravity = 9.8 m/s²
height of the track = 25 m
length of spring compressed = ?
using conservation of energy
potential energy is converted into spring energy
x = 5.79 m
the spring is compressed to x = 5.79 m to stop the car.
Given that,
Time = 0.5 s
Acceleration = 10 m/s²
(I). We need to calculate the speed of apple
Using equation of motion
Where, v = speed
u = initial speed
a = acceleration
t = time
Put the value into the formula
(III). We need to calculate the height of the branch of the tree from the ground
Using equation of motion
Put the value into the formula
(II). We need to calculate the average velocity during 0.5 sec
Using formula of average velocity
Where, = final position
= initial position
Put the value into the formula
Hence, (I). The speed of apple is 5 m/s.
(II). The average velocity during 0.5 sec is 2.5 m/s
(III). The height of the branch of the tree from the ground is 1.25 m.
Answer:
Mc = 1920[lb*in]
Explanation:
Para poder solucionar este problema debemos realizar un análisis estático, por tal motivo lo primero es realizar un diagrama de cuerpo libre con las respectivas fuerzas actuando sobre la barra ABC. DE igual manera calcular la geometría de la configuración mostrada.
El diagrama de cuerpo libre se puede ver en la imagen adjunta, con la solución de este problema.
Lo primero es determinar el angulo t, el cual por medio de las propiedades del triangulo rectángulo se puede determinar.
Con este angulo (t) ya determinado, fijamos la atención en el triangulo BCD, este triangulo no es rectángulo, pero por medio de la ley de senos podemos determinar el angulo omega.
Después de determinar el angulo omega, restamos el angulo (t) para poder determinar el angulo (a).
Seguidamente realizamos una sumatoria de momentos alrededor del punto C, utilizado las respectivas fuerzas con los ángulos descompuestos.
El momento en el punto C es de 1920 [Lb*in].
Nota: ya que no se menciona la fuerza en el punto A, esta se desprecia y no se tiene en cuenta en los calculos. En la imagen adjunta se puede ver el procedimiento desarrollado.
