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julia-pushkina [17]
3 years ago
15

Consider the following kinds of electromagnetic waves:

Physics
1 answer:
marysya [2.9K]3 years ago
7 0

Answer:

According to wavelengths in descending order: C, B, D, E and A

According to frequencies in descending order: A, E, D, B and C

According to speeds in vacuum: A =B =C =D =E

Explanation:

in the EM spectrum, radio waves have the longest wavelength while gamma rays have the shortest wavelength.

All EM waves travel with the same speed of 3*10^8m/s in a vacuum.

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A ball is kicked horizontally at 4.6 m/s off of a cliff 13.4 m high. How far from the cliff will it land.
Mekhanik [1.2K]
<h3>Answer:</h3>

7.53 m

<h3>Explanation:</h3>

<u>We are given:</u>

Initial Horizontal Velocity of the Ball = 4.6 m/s

Initial Vertical Velocity of the Ball = 0 m/s

Height from which ball is kicked = 13.4 m

<u>Time taken by the ball to reach the ground:</u>

The ball has an initial vertical velocity of 0 m/s

it also has a downward acceleration of 10 m/s² due to gravity

<u>Solving for the time taken:</u>

s = ut + 1/2(at²)                 [second equation of motion]

replacing the values

13.4 = (0)(t) + 1/2 (10)(t²)

13.4 = 5t²

t² = 13.4/5                  [dividing both sides by 5]

t² = 2.68

t = 1.637 seconds     [taking the square root of both sides]

<u>Horizontal distance covered by the ball:</u>

Since there are no horizontal opposing forces on the ball,

the ball will more horizontally at a velocity of 4.6 m/s until it hits the ground

We calculated that the ball will hit the ground in 1.637 seconds

<u>Distance covered:</u>

s = ut + 1/2 (at²)                            [seconds equation of motion]

s = ut                                            [since a = 0m/s² in the horizontal plane]

replacing the values

s = 4.6 * 1.637

s = 7.53 m

Hence, the ball landed 7.53 m from the cliff

5 0
3 years ago
Which would hit the ground first if dropped from the same height in a vacuum—a feather or a metal bolt?
vovikov84 [41]
They hit the ground at the same time
4 0
3 years ago
The law of repulsion by Coulomb agrees with: Newton's law of universal gravitation Newton's laws of motion the findings of Gilbe
s344n2d4d5 [400]

Explanation:

The law of repulsion is given by Coulomb. The mathematical form of Coulomb law is given by :

F=\dfrac{kq_1q_2}{r^2}...............(1)

Where

F is the force

k is the electrostatic constant

q_1\ and\ q_2 are electric charges

r is the distance between charges

The Newton's law of universal gravitation is given by :

F=\dfrac{Gm_1m_2}{r^2}..............(2)

G is the universal gravitational constant

From equation (1) and (2) it is clear that both law obeys inverse square law and both are of same type. So, the law of repulsion by Coulomb agrees with the Newton's law of universal gravitation.

7 0
3 years ago
A brush fire is burning on a rock ledge on one side of a ravine that is 25 m wide. A fire truck sits on the opposite side of the
Ierofanga [76]

Answer:

v_o = 30.5 m/s

Explanation:

Height of the hose pipe is given as

y = 4.5 m

horizontal distance is given as

x = 25 m

angle of elevation is given as 35 degree with the horizontal

now we know that the horizontal distance moved is given as

x = (v_ocos35) t

y = 4.5 + (v_o sin35) t - \frac{1}{2}(9.8)t^2

now we have

25 = v_o(0.82)t

also we have

0 = 4.5 + 0.57 v_o t - 4.9 t^2

0 = 4.5 + (0.57)(0.82) - 4.9 t^2

t = 1.00 s

so we have

v_o = 30.5 m/s

8 0
3 years ago
Somebody please help me!! Timed test
Olegator [25]

Answer: i dont know sorry

Explanation:

3 0
3 years ago
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