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irina [24]
3 years ago
13

Which particle changes the mass of the isotope the most? which particle changes the mass of the isotope the most? electron captu

re positron emission gamma capture alpha particle neutron particle?
Chemistry
2 answers:
MAXImum [283]3 years ago
7 0
This question is absurd
masha68 [24]3 years ago
5 0

Answer: Option (d) is the correct answer.

Explanation:

Species which contain same number of protons but different number of neutrons are known as isotope.  

For example, ^{1}_{1}H and ^{3}_{1}H are isotopes.

More is the mass of particle colliding with the isotope more will be the change in mass of an isotope due to emission of a heavier particle.

As alpha (^{4}_{2}He) particle is heavier then a neutron, positron and gamma particles.

For example, ^{14}_{7}N + ^{4}_{2}He \rightarrow ^{17}_{8}O

Therefore, we can conclude that alpha particle changes the mass of the isotope the most.

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Consider a disubstituted aromatic compound. The parent name is benzene and there is a chloro and bromo substituent. Disubstitute
Marina86 [1]

Answer:The correct names for the structure are:

--> 1. 1-bromo-3-chlorobenzene.

--> 3. meta-bromochlorobenzene.

--> 6. m-bromochlorobenzene.

Explanation:

Benzene is the simplest member of the aromatic hydrocarbons. It has a ring structure consisting of six carbon and six hydrogen atoms. This equally means that a benzene can have up to six substituents. One of the chemical properties is that benzene and other members of its series undergo substitution reaction whereby one or more of its six hydrogen atoms is replaced by monoatomic reagents.

Disubstituted benzene consists of two substituents which are described based on either numerical locants or specific words for the three possible forms.

The numerical locant method are used the same naming substitutes of other hydrocarbons. From the question, the numerical locant method was derived through using the following steps:

--> the functional group is benzene

--> there are two substituents which includes bromine( written as bromo) and chlorine ( written as chloro)

--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.

The second naming method for a disubstituted benzene is the the ortho-, meta-, para- (or their singel letter equivalent) nomenclature method. This is only used for benzene structures.

--> ortho or O : this is used when the substituents are close to each other in the benzene ring.

--> meta or (m) : This is used when the substituents are separated by one carbon in the benzene ring.

--> para or (p): This is used when the substituents are across each other in the benzene ring

From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.

8 0
3 years ago
Which part of the experiment is not touched by the independent variable or is the normal/comparison
kobusy [5.1K]
The part of the experiment that’s is not touched by the independent variable and is for comparison is called the :
Control Group
8 0
3 years ago
The air in a living room has a mass of 60 Kg and a specific heat of 1,020 J/kg°C. What is the change in thermal energy of the ai
arlik [135]

Answer:

Q = 306 kJ

Explanation:

Given that,

Mass, m = 60 kg

Specific heat, c = 1020 J/kg°C

The temperature changes from 20°C to 25°C.

Let Q be the change in thermal energy. The formula for the heat released is given by :

Q=mc\Delta T

Put all the values,

Q=60\times 1020\times (25-20)\\\\Q=306000\ J\\\\or\\\\Q=306\ kJ

So, 306 kJ is the change in thermal energy.

4 0
3 years ago
The summary or ending of your experiment​
Katyanochek1 [597]

Answer:

Conclusion

Explanation:

I believe you were asking for the term that best matches with the description given. Typically the conclusion summarizes your experiment in a 1 to 2 paragraph format.

7 0
4 years ago
A liquid has a density of 1.17 g/cm3, how many liters of the liquid have a mass of 3.75 kg
Luda [366]
<span>There are 1000 cm3 in 1 liters. Hence 1 liter of the liquid would weigh: 1000 cm3 x (1.17 g/cm3) = 1170 gm and there are 1000 gm in 1 kg, so we want enough liters to have a mass of 3.75 kg x 1000 gm/kg = 3750 gm Hence, # of liters = desired mass / # of gm per liter = 3750 gm / 1170 gm/liter = 3.2051282 liters</span>
5 0
3 years ago
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