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irina [24]
3 years ago
13

Which particle changes the mass of the isotope the most? which particle changes the mass of the isotope the most? electron captu

re positron emission gamma capture alpha particle neutron particle?
Chemistry
2 answers:
MAXImum [283]3 years ago
7 0
This question is absurd
masha68 [24]3 years ago
5 0

Answer: Option (d) is the correct answer.

Explanation:

Species which contain same number of protons but different number of neutrons are known as isotope.  

For example, ^{1}_{1}H and ^{3}_{1}H are isotopes.

More is the mass of particle colliding with the isotope more will be the change in mass of an isotope due to emission of a heavier particle.

As alpha (^{4}_{2}He) particle is heavier then a neutron, positron and gamma particles.

For example, ^{14}_{7}N + ^{4}_{2}He \rightarrow ^{17}_{8}O

Therefore, we can conclude that alpha particle changes the mass of the isotope the most.

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Gre4nikov [31]

Answer:

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Explanation:

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3 0
3 years ago
Read 2 more answers
What is the number of moles in 15.0 g AsH3?
pentagon [3]

We are given with the mass of Arsine (AsH_{3}

The mass of arsine is 15g

there is a relation between moles, mass and molar mass of any compound which is

moles=\frac{mass}{molarmass}

The molar mass of Arsine = atomic mass of As + 3X atomic mass of H

the molar mass of Arsine = 74.92 + 3X 1 = 77.92 g/mol

Let us calculate the moles as

moles=\frac{15}{77.92}=0.192mol


7 0
2 years ago
What is the origin of the name for bismuth
Juliette [100K]
The name come from the German 'Bisemutum' a corruption of 'Weisse Masse' meaning white mass. 
6 0
3 years ago
The enthalpy of fusion of solid n-butane is 4.66 kJ/mol. Calculate the energy required to melt 58.3 g of solid n-butane.
adelina 88 [10]

Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

Explanation :

First we have to calculate the moles of n-butane.

\text{Moles of n-butane}=\frac{\text{Mass of n-butane}}{\text{Molar mass of n-butane}}

Given:

Molar mass of n-butane = 58.12 g/mole

Mass of n-butane = 58.3 g

Now put all the given values in the above expression, we get:

\text{Moles of n-butane}=\frac{58.3g}{58.12g/mol}=1.00mol

Now we have to calculate the energy required.

Q=\frac{\Delta H}{n}

where,

Q = energy required

\Delta H = enthalpy of fusion of solid n-butane = 4.66 kJ/mol

n = moles = 1.00 mol

Now put all the given values in the above expression, we get:

Q=\frac{4.66kJ/mol}{1.00mol}=4.66kJ

Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

7 0
2 years ago
HELP ME PLEASE!!!! I NEEDZ HELP!!!
Anuta_ua [19.1K]
It goes Meter mega meter giga meter and kilometer
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2 years ago
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