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3 years ago

During active transport, substances move from regions of blank concentration to regions of blank concentration

1 answer:

4 0

<span>Active transport runs counter to facilitated diffusion. In active transport, molecules move against the concentration gradients, running from areas of lower concentration to areas of higher concentration. This is where energy is used.</span>

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A balloon vendor at a street fair is using a tank of helium to fill her balloons. The tank has a volume of 124.0 L and a pressur

amm1812

Answer:

She lost 50.88 moles

Explanation:

Step 1: Data given

The volume of the tank = 124.0 L

The initial pressure = 104.0 atm

The temperature = 24.0 °C = 297 K

The pressure drops to 94.0 atm

The temperature stays constant at 297 K

Step 2: Calculate the initial number of moles

p*V = n*R*T

n = (p*V)/(R*T)

⇒with p = the initial pressure = 104.0 atm

⇒with V = the initial volume = 124.0 L

⇒with n = the initial number of moles = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = the temperature= 297 K

n = (104.0*124.0)/(0.08206*297)

n = 529.14 moles

Step 3: Calculate final number of moles

p*V = n*R*T

n = (p*V)/(R*T)

⇒with p = the initial pressure = 94.0 atm

⇒with V = the initial volume = 124.0 L

⇒with n = the initial number of moles = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = the temperature= 297 K

n = (94.0*124.0)/(0.08206*297)

n = 478.26 moles

Step 4: Calculate the difference of moles

529.14 moles - 478.26 moles = 50.88 moles

She lost 50.88 moles

4 0

3 years ago

Any help with these questions would help i'm lost

SSSSS [86.1K]

Answer:

1. 31.25 mL

2. 1.98 g/L

3. 0.45 g/mL

Explanation:

For each of the problems, you need to perform unit conversions. You need to use the information given to you to convert to a specific unit.

1. You need volume (mL). You have density (g/mL) and mass (g). Divide mass by density. You will cancel out mL and be left with g.

(50.0 g)/(1.60 g/mL) = 31.25 mL

2. You are given grams and liters. You need to find density with units g/L. This means that you have to divide grams by liters.

(0.891 g)/(0.450 L) = 1.98 g/L

3. You have to find density again but this time with units g/mL. Divide the given mass by the volume.

(10.0 g)/(22.0 mL) = 0.45 g/mL

5 0

3 years ago

Which of the following does not state a property of electricity?

vagabundo [1.1K]

D, It is a flow of protons, is the best answer. Electricity is the flow of electrons, not protons.

3 0

2 years ago

Read 2 more answers

For the following reaction, 22.0 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas . nitrogen mono

mash [69]

NO is the limiting reagent and 4.34 g is the amount of the excess reagent that remains after the reaction is complete

<h3>What is a limiting reagent?</h3>

The reactant that is entirely used up in a reaction is called as limiting reagent.

The reaction:

$2NO(g) +2H_2(g)$ → $N_2 +2H_2O$

Moles of nitrogen monoxide

Molecular weight: $M_(_N_O_)$ =30g/mol

$n_(_N_O_) =\frac{mass}{molar \;mass}$

$n_(_N_O_) =\frac{22.0}{30g/mol}$

$n_(_N_O_) = 0.73 mol$

Moles of hydrogen

Molecular weight: $M_(_H_2_)$ =30g/mol

$n_(_H_2_) =\frac{mass}{molar \;mass}$

$n_(_H_2_) =\frac{5.80g}{2g/mol}$

$n_(_H_2_) = 2.9 mol$

Hydrogen gas is in excess.

NO is the limiting reagent.

The amount of the excess reagent remains after the reaction is complete.

$n_(_N_2_) =$ (2.9 mol- 0.73 mol NO x $\frac{1 \;mol \;of \;H_2}{2 \;mole \;of \;NO}$ ) x $\frac{2g \;of \;H_2}{mole \;of \;H_2}$

$n_(_N_2_) =$ 4.34 g

Learn more about limiting reagents here:

brainly.com/question/26905271

#SPJ1

5 0

1 year ago

The mole fraction of nitrogen in the air is 0.7808. this means that 78.08% of the molecules in the air are nitrogen. when the at

Pachacha [2.7K]

Answer:

$p = \boxed{\text{593 torr}}$

Explanation:

For this question, we must use Dalton's Law of Partial Pressures:

The partial pressure of a gas in a mixture of gases equals its mole fraction times the total pressure:

$p = \chi p_{\text{tot}}$

Data:

χ = 0.7808

$p_{\text{tot}} = \text{ 760 torr}$

Calculation:

$p = 0.7808 \times \text{ 760 torr}\\\\p= \boxed{\textbf{593 torr}}$

7 0

2 years ago