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Mekhanik [1.2K]
3 years ago
10

The value of 'g' differs from place to place .Why?​

Physics
1 answer:
LiRa [457]3 years ago
8 0

Answer:

<h3>وذلك بسبب اختلاف نصف القطر من مكان لاخر, حيث ان التعجيل الارضي يعتمد على نصف القطر للكوكب بشكل اساسي.</h3>

Explanation:

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PLEASE HELP QUICKLY!!!!!
Grace [21]

Answer:

D air

Explanation:

it is not found on the periodic table

brainliest plsssssssssssssssss

3 0
3 years ago
The temperature of a gas is increased from 125 celsius inside a rigid container. The original pressure of a gas was 1.22atm, wha
Sonja [21]

The temperature of a gas is increased from 125 celsius inside a rigid container. The original pressure of a gas was 1.22atm, what will the pressure of a gas be after the temperature changes?

8 0
3 years ago
What are the factors that affect the size of an impact crater?
tatiyna

Answer:

The following factors could be responsible for size of an Impact Crater:

  • Geography of the region where it impacted.
  • Size of the Impactor
  • Velocity of the Impactor

Hope it helps!<3

5 0
3 years ago
Consider a metal single crystal oriented such that the normal to the slip plane and the slip direction are at angles of 60 and 3
Scilla [17]

Explanation:

Given that,

Angle by the normal to the slip α= 60°

Angle by the slip direction with the tensile axis β= 35°

Shear stress = 6.2 MPa

Applied stress = 12 MPa

We need to calculate the shear stress applied at the slip plane

Using formula of shear stress

\tau=\sigma\cos\alpha\cos\beta

Put the value into the formula

\tau=12\cos60\times\cos35

\tau=4.91\ MPa

Since, the shear stress applied at the slip plane is less than the critical resolved shear stress

So, The crystal will not yield.

Now, We need to calculate the applied stress necessary for the crystal to yield

Using formula of stress

\sigma=\dfrac{\tau_{c}}{\cos\alpha\cos\beta}

Put the value into the formula

\sigma=\dfrac{6.2}{\cos60\cos35}

\sigma=15.13\ MPa

Hence, This is the required solution.

3 0
3 years ago
A coin is placed on a large disk which rotates uniformly at a rate of 1 rot/s. The coefficient of friction between the coin and
s2008m [1.1K]

Answer:

r = 0.02 m

Explanation:

from the question we have :

speed = 1 rps = 1x 60 = 60 rpm

coefficient of friction (μ) = 0.1

acceleration due to gravity (g) = 9.8 m/s^{2}

maximum distance without falling off (r) = ?

to get how far from the center of the disk the coin can be placed without having to slip off we equate the formula for the centrifugal force with the frictional force on the turntable force

mv^2 / r =  m x g x μ

v^2 / r =  g x μ  .......equation 1

where

velocity (v) = angular speed (rads/seconds) x radius

angular speed (rads/seconds) = (\frac{2π}{60} ) x rpm

angular speed (rads/seconds) = (\frac{2 x π}{60} ) x 60 = 6.28 rads/ seconds

now

velocity = 6.28 x r = 6.28 r

now substituting the value of velocity into equation 1

v^2 / r =  g x μ

(6.28r)^2 / r = 9.8 x 0.1

39.5 x r = 0.98

r = 0.02 m

6 0
3 years ago
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