An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 23.0 days on average to co
mplete one nearly circular revolution around the unnamed planet. If the distance from the center of the moon to the surface of the planet is 2.060×105 km and the planet has a radius of 4.000×103 km, calculate the moon's radial acceleration a=_________m/s^2
1 answer:
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Answer:
2) 433 mph
Explanation:
The final velocity of the raindrop as it reaches the ground can be found by using the equation for a uniformly accelerated motion:
where
v is the final velocity
u = 0 is the initial velocity (the raindrop starts from rest)
a = g = 9.8 m/s^2 is the acceleration due to gravity
d = 2 km = 2000 m is the distance covered
Solving for v,
And keeping in mind that
1 mile = 1609 metres
1 hour = 3600 s
The speed converted into miles per hour is
Answer:
a)F=3 x 10⁻⁷ N
b)x=2.405 m
Explanation:
Given that
m₁=295 kg
m₂=595 kg
d= 4.1 m
a)
m₃=63 kg
r=d/2 = 2.05 m
The force between the mass m₁ and m₃
by putting the values
F₁₃=2.94 x 10⁻⁷ N
The force between the mass m₂ and m₃
by putting the values
F₂₃=5.94 x 10⁻⁷ N
The net force F
F= F₂₃- F₁₃
F=5.94 x 10⁻⁷ N-2.94 x 10⁻⁷ N
F=3 x 10⁻⁷ N
b)
Lest take at distance x from mass m₂ net force is zero.
Form above two equation
x²=2.01(4.1-x)²
x=1.42 (4.1-x)
x=5.82 - 1.42x
x=2.405 m
