An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 23.0 days on average to co
mplete one nearly circular revolution around the unnamed planet. If the distance from the center of the moon to the surface of the planet is 2.060×105 km and the planet has a radius of 4.000×103 km, calculate the moon's radial acceleration a=_________m/s^2
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Answer:
The tension is 384 N.
Explanation:
To calculate the acceleration, we know the velocity and the time, so:
a=Δv/t
To calculate the tension we need to apply Newton's second law:
∑F=m*a
Answer: 104.026 m/s=374.49 km/h
Explanation:
When a body or object falls, basically two forces act on it:
1. The force of air friction, also called "drag force" :
(1)
Where:
is the drag coefficient
is the density of the fluid (air in this case)
is the velocity
is the transversal area of the object
So, this force is proportional to the transversal area of the falling element and to the square of the velocity.
2. Its weight due to the gravity force :
(2)
Where:
is the mass of the object
is the acceleration due gravity
(3)
(4)
(5) This is the terminal velocity
Substituting the known values in (5):
(6)
Then:
This is the final velocity in meters per second
Now, let's find the final velocity in kilometers per hour, knowing and
:
This is the final velocity in kilometers per hour.