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fiasKO [112]
3 years ago
6

1. Calculate the charge in a circuit which carries a current of 30 amperes for 5 seconds

Physics
1 answer:
sweet-ann [11.9K]3 years ago
6 0

Answer:

1. 150C.

2. 50sec

3.1.5a

Explanation:

1. I = Q/T

Q= 30x5

=150c

2.applying the formulae, I = Q/T

T= Q/I

=500/10

=50sec.

3. using the formulae i=q/t

i= 120/80

=1.5a.

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# A cheetah can start from rest and attain the velocity 72km/h in 2 seconds. Calculate the acceleration of cheetah
yan [13]

Answer:

<h2>10 \: m/s ^2</h2><h2 />

Explanation:

Solution,

When a certain object comes in motion from rest, in the case, initial velocity = 0 m/s

Initial velocity ( u ) = 0 m/s

Final velocity ( v ) = 72 km/h ( Given)

We have to convert 72 km /h in m/s

72 \: km \: per \: hour

= 72 \times  \frac{1000}{60  \times 60}

= 20 m/s

Final velocity ( v ) = 20 m/s

Time taken ( t ) = 2 seconds

Acceleration (a) = ?

Now,

we have,

a =  \frac{v - u}{t}

a =  \frac{20 - 0}{2}

a =  \frac{20}{2}

a = 10 m/s ^2

Hope this helps...

Good luck on your assignment..

7 0
3 years ago
A tray of electronic components contains 15 components, 4 of which are defective. If 4 components are selected, what is the poss
dlinn [17]

Answer:

a) 0.0007326

b) 0.03223

c) 0.2418

d) 0.2418

Explanation:

To find different probabilities for the selection of components among eleven good and four defective components, we will use the Combination.

a) C(4,4) = 1; C(15,4) = 1365

P = \frac{C(4,4)}{C(15,4)} = \frac{1}{1365} = 0.0007326

b) C(4,3) = 4; C(11,1) = 11

P = \frac{C(4,3)*C(11,1)}{C(15,4)} = \frac{4*11}{1365} = 0.03223

c) C(4,2) = 6; C(11,2) = 55

P = \frac{C(4,2)*C(11,2)}{C(15,4)} = \frac{6*55}{1365} = 0.2418

d) C(11,4) = 330

P = \frac{C(11,4)}{C(15,4)} = \frac{330}{1365} = 0.2418

8 0
3 years ago
a swimmer experiences a total (absolute) pressure of 117,500 pa in a pool. how far below the surface are they located?
marta [7]

Answer:

Explanation:

We know that the pressure can be calculated in the following way:

p = d·g·h

with d being the density of the water, g the gravitational acceleration and h the depth.

Also d of the water = 1000 kg/m^3 circa and g = 9.8 m/s^2 circa

117,500 Pa = 1000kg/m³ · 9.8m/s² · h

Therefore h = 11,9 m

4 0
2 years ago
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6 0
3 years ago
Which condition is required for Coulomb's law to hold true?
AleksAgata [21]
The correct answer is:
<span>Point charges must be in a vacuum.

In fact, the usual form for of the Coulomb's law is:
</span>F= \frac{1}{4 \pi \epsilon_0}  \frac{q_1 q_2}{r^2}
<span>where
</span>\epsilon_0 is the permittivity of free space
<span>q1 and q2 are the two charges
q is the separation between the two charges

However, this formula is valid only if the charges are in vacuum. If they are in a material medium, the law is modified as follows:
</span>F= \frac{1}{4 \pi \epsilon_0 \epsilon_r} \frac{q_1 q_2}{r^2}
where \epsilon_r is the relative permittivity, which takes into account the dielectric effects of the material.
7 0
3 years ago
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