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shusha [124]
3 years ago
15

Instructions:Select all the correct answers.

Physics
2 answers:
____ [38]3 years ago
3 0
Choice (3) would be one of the objects because when its stretching its waiting to release the energy. Then choice (1) would be the other object because when it rolls  the energy stored in the ball would be released when stopped. Therefore there storing the energy until released.  
V125BC [204]3 years ago
3 0

Answer:

2. A small rock sitting on the top of big rock.

3. a stretched rubber band.

Explanation:

The potential energy is defined as the energy by the virtue of the position of the object, its electric energy, stress which present in itself.

There are the two forms of potential energies which are more common:

  • Gravitational potential energy: It is a form of potential energy which depends on the mass of an object and the distance of that object from the center of the earth. In the given situation the rock which is sitting on the top of big rock posses gravitational potential energy.
  • Elastic potential energy: It is the form of energy which is produced by the virtue of extending spring. This energy in this is the store energy of the extending or compressed spring. In the given situation a stretched rubber band is the example of elastic potential energy.

Therefore, in the given problem a stretched rubber band and  a small rock which is sitting on the top of big rock have stored energy.

You might be interested in
A 3 kg rock sits on a 0.8 meter ledge. If it is pushed off, how fast will it be going at the bottom?
andrey2020 [161]

As long as it sits on the shelf, its potential energy
relative to the floor is . . .

   Potential energy =      (mass) x (gravity) x (height) =

                                       (3 kg) x (9.8 m/s²) x (0.8m) = <u>23.52 joules</u> .

If it falls from the shelf and lands on the floor, then it has exactly that
same amount of energy when it hits the floor, only now the 23.52 joules
has changed to kinetic energy.

   Kinetic energy =                                          (1/2) x (mass) x (speed)²

                                                 23.52 joules = (1/2) x (3 kg) x (speed)²

Divide each side by  1.5 kg :     23.52 m²/s² = speed²

Take the square root of each side:    speed = √(23.52 m²/s²) =  <em>4.85 m/s </em> (rounded)


6 0
3 years ago
During an experiment, Ellie records a measurement of 0.0034 m. How would
Goshia [24]

Answer:

(A)   She needs to move the decimal point by 3 places

8 0
3 years ago
Sarah and Maisie are analysing data from their school sports day. Looking at the 1500 m results for Stephen, Maisie believes tha
Dahasolnce [82]

Answer:

Sarah is right

Explanation:

This is an exercise that differentiates between scalars and vectors.

A scalar is a number, instead a vector is a number that represents the module in addition to direction and sense.

In this case, the distance (scalar) traveled is a number, which is why it is worth 1500m, but the displacement is a vector and since the point where it leaves is the same point where the vector's modulus arrives is zero, so the DISPLACEMENT VECTOR is zero

consequently Sarah is right

4 0
2 years ago
What is the momentum of a 12 kg condor flying at 6 m/s?
rusak2 [61]

Answer:

72

Explanation:

Formula

p=mv\\=12*6\\=72

5 0
3 years ago
A horizontal uniform meter stick supported at the 50-cm mark has a mass of 0.50 kg hanging from it at the 20-cm mark and a 0.30
ElenaW [278]

Answer:

70 cm

Explanation:

0.5 kg at 20 cm

0.3 kg at 60 cm

x = Distance of the third 0.6 kg mass

Meter stick hanging at 50 cm

Torque about the support point is given by (torque is conserved)

0.5(50-20)=0.3(60-50)+0.6x\\\Rightarrow x=\dfrac{0.5(50-20)-0.3(60-50)}{0.6}\\\Rightarrow x=20\ cm

The position of the third mass of 0.6 kg is at 20+50 = 70 cm

7 0
3 years ago
Read 2 more answers
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