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Y_Kistochka [10]
3 years ago
8

A 2-kg box sits on a horizontal table. the force of friction between the box and the table is 10 n. the box is pushed to the rig

ht with an applied horizontal force of 20 n. what is the acceleration of the box?
Physics
1 answer:
dangina [55]3 years ago
6 0
By Newton's 2nd law of motion, F = ma, where F is force, m is mass, and a is acceleration.

Rearranging this equation to find acceleration would give us:
a = F/m

The horizontal force to the right is 10N, because the box is pushed to the right with a force of 20N, and the friction force of 10N opposes that, so:
20N - 10N = 10N

The mass is 2kg.

Putting these values into the equation gives us:
a = F/m
= 10/2
= 5ms^-2

The acceleration of the box is 5ms^-2
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<span>The correct answer is blue. If you look at a luminosity star chart, called the Hertzsprung Russell Diagram, you will see the measurement of luminosity on the left side, and you will see a curve of stars with different colors (which correlate to the colors of the stars). Look for 30 on the luminosity measurement (look between 1 and 100). Then, move horizontally across the diagram until you hit the stars, whose color will be blue. Thus, blue is the answer.</span>
5 0
3 years ago
A parallel-plate capacitor with circular plates of radius R is being charged by a battery, which provides a constant current. At
NikAS [45]

To solve this problem it is necessary to apply the concepts related to the magnetic field.

According to the information, the magnetic field INSIDE the plates is,

B=\frac{1}{2} \mu \epsilon_0 r

Where,

\mu =Permeability constant

\epsilon_0 =Electromotive force

r = Radius

From this deduction we can verify that the distance is proportional to the field

B \propto r

Then the distance relationship would be given by

\frac{r}{R} = \frac{B}{B_{max}}

r =\frac{B}{B_{max}} R

r = \frac{0.5B_{max}}{B_{max}}R

r = 0.5R

On the outside, however, it is defined by

B = \frac{\mu_0 i_d}{2\pi r}

Here the magnetic field is inversely proportional to the distance, that is

B \not\propto r

Then,

\frac{r}{R} = \frac{B_{max}{B}}

r = \frac{B_{max}{B}}R

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7 0
3 years ago
Is there ever a situation where an ant will have more momentum than an elephant? Explain why or why not?
Mariulka [41]

Answer:

Yes

Explanation:

The momentum of an object is given by:

p=mv

where

m is the mass of the object

v is the velocity of the object

We know that an elephant has a mass much larger than the mass of an ant. However, we see that the momentum of the animal also depends on its velocity.

If the elephant is at rest, its velocity is zero:

v = 0

so its momentum is also zero:

p = 0

And therefore, an ant which is moving (so, non-zero speed) can have more momentum than an elephant, if the elephant is at rest.

6 0
3 years ago
The equation y = 5 Sin (3x - 4t), where
igomit [66]

Answer:

Frequency, f = 0.63 Hz

Period, T = 1.58 s

Speed of a wave, v = 1.34 m/s

Explanation:

The equation of a wave is given by :

y = 5 \sin (3x - 4t) ...(1)

y is in mm

x is in meters

t is in seconds

The general equation of a wave is given by :

y=A\sin(kx-\omega t) ...(2)

(i) Compare equation (1) and (2) we get :

k=3\\\\\omega=4

Since,

\omega=2\pi f\\\\f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{4}{2\pi}\\\\f=0.63\ Hz

(ii) Period of wave is :

T=\dfrac{1}{f}\\\\T=\dfrac{1}{0.63}\\\\T=1.58\ s

(iii) Speed of a wave,

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4 0
3 years ago
If I were to fill a water bottle full of air and go up in elevation, would the water bottle expand or shrink? If I were to fill
alina1380 [7]

Answer:

a. It would shrink

b. It would expand

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a. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure decreases with altitude, when we go up in elevation.

The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go higher. Since the atmospheric pressure exerted by the molecules of air in the atmosphere are greater than that exerted by the molecules of air in the water bottle, this causes the volume of the water bottle to decrease and thus shrinks the water bottle until the pressure balances out

b. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure increases with decreasing altitude, when we go down in elevation.

The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go lower. The water bottle expands until the atmospheric pressure outside equals the pressure inside the water bottle.this causes the volume of the water bottle to increase and thus expands the water bottle until the pressure balances out

4 0
3 years ago
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