You just found a metallic object in a creek bed. You have found its mass to be 96.5 g, and it displaces 5 mL of water. What is t
2 answers:
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Explanation:
Formation of formate buffer will be as follows.
Formate buffer = HCOOH + HCOONa
Molar mass of HCOOH = 46 g/mol
Molar mass of HCOONa = 68 g/mol
of HCOOH = 3.75
As, = [HCOOH] + [HCOONa]
= [HCOONa] (here, dissociation of HCOOH is negligible)
Its preparation will be as follows.
750 ml of 0.25 M sodium formate buffer
Since, there are many combinations of salt + acid and among those possibilities one of them is as follows.
HCOONa = 0.25 M in 400 ml solution
HCOOH = x molat in 350 ml solution
Therefore as, pH =
4 = 3.75 +
x = 0.16 M
Therefore, molarity of the formic acid acid is 0.16 M.
Now, calculate the weight of sodium formate as follows.
= 6.8 g
And, number of milliliters of formic acid required is 350 ml.