Cartography is the science of

A cannonball is fired horizontally with an initial velocity of 20 m/s off a cliff that is 10 m from the ground. if the initial v

Dominik [7]

Consider the motion of the cannonball along the vertical direction or y-direction.

$v_{oy}$ = initial velocity along the Y-direction

$a_{y}$ = acceleration due to gravity

t = time of travel

Y = vertical displacement

Using the kinematics equation

Y = $v_{oy}$ t + (0.5) $a_{y}$ t²

since the ball has been launched horizontally , $v_{oy}$ = 0

Y = (0) t + (0.5) $a_{y}$ t²

t = $\frac{2Y}{a_{y}}$

hence the time of travel is independent of the initial velocity. hence the time of travel remain same.

Consider the motion along the horizontal direction

$v_{ox}$ = initial velocity along the X-direction

$a_{x}$ = acceleration along the horizontal direction = 0

t = time of travel

X = horizontal displacement

Using the kinematics equation

X = $v_{ox}$ t + (0.5) $a_{x}$ t²

since the ball has been launched horizontally , $a_{x}$ = 0

X = $v_{ox}$ t + (0.5) (0) t²

X = $v_{ox}$ t

hence the horizontal distance directly depends on the velocity. so the horizontal distance will become double.

C) The time won't change, but horizontal distance will double.

8 0

3 years ago

Read 2 more answers

(a) What is the ionization energy of a hydrogen atom that is in the n = 6 excited state? (b) For a hydrogen atom, determine the

crimeas [40]

Answer:

(a) 0.3778 eV

(b) Ratio = 0.0278

Explanation:

The Bohr's formula for the calculation of the energy of the electron in nth orbit is:

$E=\frac {-13.6}{n^2}\ eV$

(a) The energy of the electron in n= 6 excited state is:

$E=\frac {-13.6}{6^2}\ eV$

$E=-0.3778\ eV$

Ionisation energy is the amount of this energy required to remove the electron. Thus, |E| = 0.3778 eV

(b) For first orbit energy is:

$E=\frac {-13.6}{1^2}\ eV$

$E=-13.6\ eV$

$Ratio=\frac {E_6}{E_1}$

$Ratio=\frac {-0.3778}{-13.6}$

Ratio = 0.0278

7 0

4 years ago

HELP ME PLEASE!!!!!!!!!

Mamont248 [21]

I'm here to help what's the question

7 0

3 years ago

why very high frequency (VHF) and ultra high frequency (UHF) radio waves are used for communications between space vehicles and

Angelina_Jolie [31]

1). Systems at higher frequencies can carry more information
(data, pictures, channels, etc.) than at lower frequencies.

2). The "dish" antennas used for satellite communication, both on
the ground and on the satellite, have more gain at higher frequencies
than they have at lower ones.

3). Radio waves at frequencies lower than VHF reflect off of the
ionized layers of the atmosphere and return to Earth. They never
get out to where the satellites are.

4). All of the communication spectrum (frequencies) below VHF
were already being used for other services by the time satellite
communication started (in the 1960's).

7 0

4 years ago

After working in a fast-food restaurant for three years to pay for your college tuition, you vowed never to work in a restaurant

devlian [24]

Answer:

The correct answer is Cognitive.

Explanation:

The psychologist Leon Festinger proposed the theory of cognitive dissonance, which explains how people try to maintain their internal consistency. He suggested that individuals have a strong inner need that pushes them to ensure that their beliefs, attitudes and behavior are consistent with each other. When there is inconsistency between them, the conflict leads to a lack of harmony, something that people strive to avoid.

This theory has been widely studied in the field of psychology and can be defined as the discomfort, tension or anxiety that individuals experience when their beliefs or attitudes conflict with what they do. This displeasure can lead to an attempt to change behavior or defend their beliefs or attitudes (even reaching self-deception) to reduce the discomfort they produce.

4 0

3 years ago

Cartography is the science of​

Cartography is the science of