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wariber [46]
3 years ago
9

The heat pump is designed to move heat. This is only possible if certain relationships between the heats and temperatures at the

hot and cold sides hold true. Indicate the statement that must apply for the heat pump to work.A. Q_{\rm h} < Q_{\rm c} and T_{\rm h} < T_{\rm c}.B. Q_{\rm h} > Q_{\rm c} and T_{\rm h} < T_{\rm c}.C. Q_{\rm h} < Q_{\rm c} and T_{\rm h} > T_{\rm c}.D. Q_{\rm h} > Q_{\rm c} and T_{\rm h} > T_{\rm c}.
Physics
1 answer:
Pie3 years ago
7 0

Answer:

There are no answer chooses to this question

Explanation:

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A ball is throw vertically upwards with a speed of 20ms,calculate the maximum height reach(g=10)
Goshia [24]
Please check the attached picture

4 0
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#3 <br> The ___________________________ filter our blood.
juin [17]

Answer:

Kidneys filter our blood,

Explanation:

Hope this helped :)

3 0
3 years ago
Read 2 more answers
A batter hits a baseball so that it leaves the bat with an initial speed of 60m/s at an initial angle of 42 with the horizontal
Elza [17]

Answer: 24.06°

Explanation:

So,we can say after t if it reaches height h then,

h = (37 sin 53)t - 1/2 * 9.8t^2 (as,vertical component of velocity is 37 sin 53)

Given t = 2s

So, h = 39.5m

And horizontal displacement will be

r = 37 cos 53 *2 = 44.52m

So,after 2s the baseball will be lying 39.57m

above its point of projection and 44.52m ahead of its point of projection.

Now.let the vertical component of velocity will become Vy after time 2s

So, Uy = 37 sin 53- 9.8* 2

or, U = 9.95m/s

And.horizontal component of velocity remains

constant i.e Vx = 37 cos 53 = 22.27m/s

So.magnitude of velocity after 2s is

Square root of (Vx^2 + Vy^2)= 24.4m/s

Making an angle of tan 22.27/9.95 = 24.06°

6 0
3 years ago
The brakes on your automobile are capable of creating a deceleration of 4.6 m/s^2. If you are going 114 km/h and suddenly see a
drek231 [11]

Answer:

The minimum time to get the car under max. speed limit of 79 km/h is 2.11 seconds.

Explanation:

a=\frac{V_f-V_0}{t}

isolating "t" from this equation:

t=\frac{V_f-V_0}{a}

Where:

a=-4.6m/s^2 (negative because is decelerating)

V_f= 79 km/h

V_0= 114 km/h

First we must convert velocity from km/h to m/s to be consistent with units.

79\frac{km}{h}*\frac{1000m}{1 km}*\frac{1h}{3600s}=\frac{79*1000}{3600}=21.94 m/s

114\frac{km}{h}*\frac{1000m}{1 km}*\frac{1h}{3600s}=\frac{114*1000}{3600}=31.67 m/s

So;

t=\frac{V_f-V_0}{a}=\frac{21.94 m/s-31.66m/s}{-4.6 m/s^2}=2.11 s

7 0
3 years ago
A force of 120 N is applied to the front of a sled so as to pull the sled a distance of 165
Marrrta [24]

Answer:

<h3>The answer is 19,800 J</h3>

Explanation:

The work done by an object can be found by using the formula

<h3>workdone = force × distance</h3>

From the question

force = 120 N

distance = 165 m

We have

work done = 120 × 165

We have the final answer as

<h3>19,800 J</h3>

Hope this helps you

8 0
3 years ago
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