Answer:
3.68 m/s
Explanation:
Full answer in the attached picture
Answer:
curves downward, below the initial velocity vector.
Explanation:
Projectile launches are generally divided into two types: the oblique throw and the free fall. The free fall of bodies consists of throwing or abandoning projectiles from a hill or any unevenness that has a height in relation to a frame (usually the ground), while the oblique launch consists of launching a projectile at an angle. any relative to a frame (usually the ground).
Regardless of the type, when reading the paragraph above, we can say that the trajectory of a projectile will always be curved down and below the initial velocity vector.
Answer: Velocity=8.26m/s
Explanation:
Acceleration=Finial velocity (V) - Initial velocity (u) ÷ Time
that is, a=v-u/t
a=1.2m/s², v=?, u=5.5m/s, t=2.3s
From a=v-u/t, make v the subject of the formula
v=at + u
v=(1.2* 2.3) + 5.5
v=2.76+5.5
v=8.26m/s
Answer:
90 C
Explanation:
Electric current: This can be defined as the rate of flow of electric charge in a circuit. This can be expressed mathematically as,
I = dQ/dt
dQ = Idt
∫dQ = ∫Idt
Q = It................................ Equation 1
Where Q = amount of charge, I = current, t = time.
Given: I = 3.6 A, t = 25 s.
Substituting into equation 1,
Q = 3.6(25)
Q = 90 C.
Hence the amount of charge passing through the cross section of the conductor = 90 C