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irinina [24]
3 years ago
6

In 1961, the reference for the atomic mass unit (amu or u) was changed from naturally occurring oxygen with a value of 16.000 u

to one based on a single isotope of carbon (carbon-12). Why was it changed
Chemistry
1 answer:
vovangra [49]3 years ago
3 0

To determine the mass of an atom in terms of atomic mass unit (a.m.u.) the standard should have the fixed mass otherwise the calculated mass of the other atoms will get error. Initially oxygen was used as the reference standard for the calculation of other atoms mass. But after the invention of different isotopes of oxygen i.e. O^{17} and O^{18} which ratios with respect to O^{16} is 1.002 the mass of standard oxygen became unstable. Thus the mass of the new atom have error. Thus in 1961 the standard reference is canged to carbon-12. After that onward the mass of the other atoms are measured with respect to carbon.

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When determining the formula for a compound, it is important to know the valence numbers of each element. Suppose you want to wr
Damm [24]

Explanation:

The valency of the element is the measure of the combining power of the element with the other atoms when the element forms compounds or molecules.

<u>Thus, valency has to known to find the how the elements have been combined and how many electrons have been lost, gain or shared.</u>

Given that:

Element A has 3 valence electrons and element B has 2 valence electrons. To find the ionic compound, the valency of the cations and the anions are interchanged and are written in subscripts. Thus,

A        B

3          2

Cross multiplying, we get the formula : A_2B_3

<u>Hence, 3 is the subscript for Element B.</u>

3 0
3 years ago
PLEASE I NEED HELP NOW!!! I WILL GIVE 25 POINTS
padilas [110]
If I did this correctly the balanced equation would be:
14H⁺+Cr₂O₇²⁻+6I⁻→3I₂+2Cr³⁺+7H₂O

oxidation half: (iodide was oxidized)
2I⁻→I₂+2e⁻

reduction half: (chromium was reduced)
14H⁺+Cr₂O₇²⁻+6e⁻→2Cr³⁺+7H₂O

H⁺ comes from the solution.  It is in the final reaction since in redox reactions the oxygen is turned into water since it can't just go away.  I multiplied the oxidation half reaction by 3 in order for both half reactions to half the same number of electrons since equal numbers of electrons need to be lost and gained for the reaction to be balanced.

I hope this helps.  Let me know if anything is unclear.
8 0
3 years ago
Use the mole concept to calculate the number of atoms that are in a 1.75-mol sample of CHCl3.
Fiesta28 [93]
This is how I got to that answer. Since we don't know how many atoms there are in a mole, we use the number 6.02 x 10^-23. Now, just plug in what you have in the equation: 

<span>1.75 moles ChCl3 x (6.02 x 10 ^-23) / 1 mole = 1.0535 x 10^-22 atoms. </span>
6 0
3 years ago
Matthew added a sample of sodium chloride to water and
viktelen [127]

Answer:

11.45

Explanation:

The ph is just 14-pOH so

14-2.55=ph=11.45

3 0
2 years ago
HELP! what's the kPa?
Rus_ich [418]

Answer:

50,662.5 kPa

Explanation:

3 0
3 years ago
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