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irinina [24]
3 years ago
6

In 1961, the reference for the atomic mass unit (amu or u) was changed from naturally occurring oxygen with a value of 16.000 u

to one based on a single isotope of carbon (carbon-12). Why was it changed
Chemistry
1 answer:
vovangra [49]3 years ago
3 0

To determine the mass of an atom in terms of atomic mass unit (a.m.u.) the standard should have the fixed mass otherwise the calculated mass of the other atoms will get error. Initially oxygen was used as the reference standard for the calculation of other atoms mass. But after the invention of different isotopes of oxygen i.e. O^{17} and O^{18} which ratios with respect to O^{16} is 1.002 the mass of standard oxygen became unstable. Thus the mass of the new atom have error. Thus in 1961 the standard reference is canged to carbon-12. After that onward the mass of the other atoms are measured with respect to carbon.

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One way in which the useful metal copper is produced is by dissolving the mineral azurite, which contains copper(II) carbonate,
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The question is incomplete, here is the complete question:

One way in which the useful metal copper is produced is by dissolving the mineral azurite, which contains copper(II) carbonate, in concentrated sulfuric acid. The sulfuric acid reacts with the copper(II) carbonate to produce a blue solution of copper(II) sulfate. Scrap iron is then added to this solution, and pure copper metal precipitates out because of the following chemical reaction:

Fe(s) + CuSO4 (aq) → Cu(s) + FeSO4 (aq)

Suppose an industrial quality-control chemist analyzes a sample from a copper processing plant in the following way. He adds powdered iron to a  200.mL copper(II) sulfate sample from the plant until no more copper will precipitate. He then washes, dries, and weighs the precipitate, and finds that it has a mass of 95.mg

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<u>Answer:</u> The concentration of copper sulfate in the sample is 0.0075 M

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of copper = 95 mg = 0.095 g     (Conversion factor:  1 g = 1000 mg)

Molar mass of copper = 63.55 g/mol

Putting values in above equation, we get:

\text{Moles of copper}=\frac{0.095g}{63.55g/mol}=0.0015mol

The given chemical equation follows:

Fe(s)+CuSO_4(aq.)\rightarrow Cu(s)+FeSO_4(aq.)

By Stoichiometry of the reaction:

1 mole of copper is formed by 1 mole of copper sulfate

So, 0.0015 moles of copper will be formed by = \frac{1}{1}\times 0.0015mol=0.0015mol of copper sulfate

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

Moles of copper sulfate = 0.0015 moles

Volume of solution = 200 mL

Putting values in above equation, we get:

\text{Molarity of the solution}=\frac{0.0015\times 1000}{200}=0.0075M

Hence, the concentration of copper sulfate in the sample is 0.0075 M

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