AH1 = m * c1 * AT1 calculate this for ice (-25C to 0C) AH2 = AHfus(1 mole)=6.01 kJ = 6010 J AH3 = m *c3 * AT3 calculat this for water (0C to 100C) AH4 = AHvap(1mole)=40.67 kJ = 40670 J AH5= m * c5 * AT5 calculate this for steam (100C to 125C)
Sum ---- AH1+AH2+AH3+AH4+AH5
Data m=18g (1mole water)
c1=specific heat ice= 2.09 J/g K c3=specific heat water= 4.18 J/g K c5=specific heat steam= 1.84 J/g K
AT = (Tend - Tinitial) as this is a difference between temperatures it doesn't matter the units Celsius or Kelvin. Kelvin (K)=Celsius (C)+273.15
AT1 = 0C - (-25C)= 25C= 273.15K - 248.15K= 25K AT3= 100C - 0C = 100C= 100K AT5= 125C - 100C= 25C=25K
MW of gas : 124.12 g/mol
<h3>Further explanation </h3>
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of density
The unit of density can be expressed in g/cm³ or kg/m³
Density formula:

ρ = density
m = mass
v = volume
glass vessel wieight = 50 g
glass vessel + liquid = 148 ⇒ liquid = 148 - 50 =98 g
volume of glass vessel :

An ideal gas :
m = 50.5 - 50 = 0.5 g
P = 760 mmHg = 1 atm
T = 300 K

Data validation → editing data → entry data → tabulation
This enables better integration, consumption and analysis of larger datasets using advanced business intelligence with analytics solutions.
<h3>What is data preparation ?</h3>
Data collection, combination, structure, and organisation are all steps in the process of preparing data for use in business intelligence (BI), analytics, and data visualisation applications.
- Data prep is a common colloquial term for data preparation. It is also referred to as "data wrangling," while other professionals use that phrase more specifically to mean "cleaning, structuring, and transforming data." This usage distinguishes data wrangling from the data pretreatment stage.
Learn more about Data preparation here:
brainly.com/question/28056387
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Answer:
The correct answer is
B.

Explanation:
Enthalpy of reaction :
It is the amount of energy released/absorbed when one mole of the substance is formed from the reactant at a constant pressure.
The enthalpy of a reaction can be calculated using :









Please note that :
The carbon monoxide , CO should be taken as C triple bond O. Not C=O .
So , the bond energy =1072 is used

Answer:
Cracking.
Explanation:
A chemical reaction can be defined as a reaction in which two or more atoms of a chemical element react to form a chemical compound. An example of a chemical reaction involving hydrocarbons is cracking.
Hydrocarbon can be defined as an organic compound that comprises of hydrogen and carbon only.
In Organic chemistry, cracking refers to the process of lowering the boiling point of a heavy, complex or long-chain hydrocarbon such as kerogens by exposing it to different environmental treatments such as hydrogen enriched catalysts, pressure or high temperatures, in order to produce smaller, lighter and more useful molecules (alkanes and alkenes) such as gasoline, diesel fuel, etc.