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romanna [79]
3 years ago
5

What was the effect of the Supreme Court case McCulloch v. Maryland?

Physics
2 answers:
AURORKA [14]3 years ago
8 0
The effect was the decision that gave congress power under the necessary and proper clause act.  States could also not impede on the valid constitutional excerpts powered by the Federal Government. 
VladimirAG [237]3 years ago
7 0

Answer and explanation;

-The decision or judgement in McCulloch v. Maryland case was so important because the Supreme Court ruled that the federal government could pass laws not expressly written in the Constitution, which was a victory by the federal government over the states.

-The Supreme court struck down Maryland's attempts to place a tax on the second National Bank of the U.S. The court reasoned that the tax would essentially be a measure to undermine federal power and that the Constitution forbids any action by the states to do so.

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A metal detector used in airports is actually a large coil of wire carrying a small current. Explain how it detects a gun, even
Alexus [3.1K]

<u>Metal detectors work by transmitting an electromagnetic field from the search coil into the ground. Any metal objects (targets) within the electromagnetic field will become energised and retransmit an electromagnetic field of their own. The detector’s search coil receives the retransmitted field and alerts the user by producing a target response. metal detectors are capable of discriminating between different target types and can be set to ignore unwanted targets. </u>

1. Search Coil

The detector’s search coil transmits the electromagnetic field into the ground and receives the return electromagnetic field from a target.

2. Transmit Electromagnetic Field (visual representation only - blue)

The transmit electromagnetic field energises targets to enable them to be detected.

3. Target

A target is any metal object that can be detected by a metal detector. In this example, the detected target is treasure, which is a good (accepted) target.

<em>hope this helps PLEASE MARK AS BRAINLIEST:)</em>

8 0
3 years ago
The _______ is responsible for absorbing the most UV radiation.
Lorico [155]

_____Mesosphere_____

5 0
3 years ago
Read 2 more answers
A 16.9 kg monkey is swinging on a 5.32 m long vine. It starts at rest, with the vine at a 43.0° angle. How fast is the monkey mo
NemiM [27]

Answer:

v = 5.7554 m/s

Explanation:

First of all we need to know if the angle of the vine is measured in the horizontal or vertical.

To do this easier, let's assume the angle is measured with the horizontal. In this case, the innitial height of the monkey will be:

h₀ = h sinα

h₀ = 5.32 sin43° = 3.6282 m

As the monkey is dropping from the innitial point which is the suspension point, is also dropping from 5.32. Then the actual height of the monkey will be:

Δh = 5.32 - 3.63 = 1.69 m

In order to calculate the speed of the monkey we need to understand that the monkey has a potential energy. This energy, because of the gravity, is converted in kinetic energy, and the value will be the same. Therefore we can say that:

Ep = Ek

From here, we can calculate the speed of the monkey.

Ep = mgΔH

Ek = 1/2 mv²

The potential energy is:

Ep = 16.9 * 9.8 * 1.69 = 279.9

Now with the kinetic energy:

1/2 * (16.9) * v² = 279.9

v² = (279.9) * 2 / 16.9

v² = 33.12

v = √33.12

<h2>v = 5.7554 m/s</h2>

Hope this helps

3 0
3 years ago
A yo-yo has a string that is 0.95 m in length. What is the period of oscillation if the yo-yo is allowed to swing back and forth
yulyashka [42]

Answer:

Explanation:

As we know the , equation of time period for simple pendulum ,

T = 2*pi*\sqrt{l/g}

hence putting values we get ,

the solution is in picture ,

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3 years ago
Three deer, A, B, and C, are grazing in a field. Deer B is located 62m from deer A at an angle of 51° north of West. Deer C is l
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Set deer A's position to be the origin. Let c be the distance from deer A to deer C. We're given that deer B is 95 m away from deer C, which means the length of the vector B-C is 95 (or C-B). Then

|B-C|^2=(B-C)\cdot(B-C)=B\cdot B-2B\cdot C+C\cdot C=|B|^2-2B\cdot C+|C|^2

|B-C|^2=|B|^2-2|B||C|\cos(180-77-51)^\circ+c^2

95^2=62^2-2(62)(c)\cos52^\circ+c^2

c^2-124\cos52^\circ c-5181=0\implies c=120\,\mathrm m

8 0
4 years ago
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