Answer:
The velocity of the particle from T = 0 s to T = 4 s is;
0.5 m/s
Explanation:
The given parameters from the graph are;
The initial displacement (covered) at time, t₁ = 0 s is x₁ = 1 m
The displacement covered at time, t₂ = 4 s is x₂ = 3 m
The graph of distance to time, from time t = 0 to time t = 4 is a straight line graph, with the velocity given by the rate of change of the displacement to the time which is dx/dt which is also the slope of the graph given as follows;
The velocity of the particle from t = 0 s to t = 4 s = 1/2 m/s = 0.5 m/s.
Using the equation;
TE = 1/2mv^2(1+2); where k = 2/5 for a solid sphere; V is the velocity, and m is the mass.
Total energy = 0.5 × 21 × 8² (7/5)
= 940.8 J
The rotational kinetic energy of the sphere is 940.8 J
Hi there!
a.
We know that:
Begin by determining the forces in the vertical direction:
W = weight of traffic light
T₁sinθ = vertical component of T₁
T₂sinθ = vertical component of T₂
b.
The ropes provide a horizontal force:
T₁cosθ = Horizontal component of T1
T₂cosθ = Horizontal component of T2
Thus:
0 = T₁cosθ - T₂cosθ
T₁cosθ = T₂cosθ
T₁ = T₂
c.
Since the angles for both ropes are the same, we can say that:
T₁ = T₂
Sum the forces:
ΣFy = T₁sinθ + T₁sinθ - W = 0
2T₁sinθ = W
d.
Now, we can begin by solving for the tensions:
2T₁sinθ = W
The smooth muscle in the wall of the bladder when stretched triggers the micturition reflex (urination).
<h3>What is a Bladder?</h3>
This is defined as a lined layers of muscle tissue that stretch to hold urine in organisms.
In older people the elasticity of the bladder is reduced which is why it makes it harder for them to hold urine for a long time.
Read more about Micturition here brainly.com/question/26493943
Answer:
Explanation:
Area of crossection, A = 7.80 cm²
Initial magnetic field, B = 0.5 T
Final magnetic field, B' = 3.3 T
Time, t = 1 s
resistance of the coil, R = 1.2 ohm
The induced emf is given by
where, Ф is the rate of change of magnetic flux.
e = 7.80 x 10^-4 x (3.3 - 0.5) / 1
e = 2.184 mV
i = e/R
i = 2.184/1.2
i = 1.82 mA
