Equation of reaction
<span>KOH+HNO3--->KNO3+H2O </span>
<span>CA=6.0M, CB=2.0M, VA=?, VB=39ml, na=1, nb=1 </span>
<span>CAVA/CBVB=na/nb </span>
<span>6*VA/2*39=1/1 </span>
<span>6VA/78=1 </span>
<span>6VA=78 </span>
<span>VA=78/6. VA=13ml. </span>
<span>VA=13ml.</span><span>
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Answer:
H2 P4 O1. Explanation: In order to calculate the Empirical formula , we will assume that we have started with 10 g of the compound.
Explanation:
The correct answer is D because the the rest will have different answers depending on the person you ask. D can be proven with facts by research
Answer:
m H2O = 56 g
Explanation:
∴ The heat ceded (-) by the Aluminum part is equal to the heat received (+) by the water:
⇒ - (mCΔT)Al = (mCΔT)H2O
∴ m Al = 25.0 g
∴ Mw Al = 26.981 g/mol
⇒ n Al = (25.0g)×(mol/26.981gAl) = 0.927 mol Al
⇒ Q Al = - (0.927 mol)(24.03 J/mol°C)(26.8 - 86.4)°C
⇒ Q Al = 1327.64 J
∴ mH2O = Q Al / ( C×ΔT) = 1327.64 J / (4.18 J/g.°C)(26.8 - 21.1)°C
⇒ mH2O = 55.722 g ≅ 56 g
Answer:

Explanation:
Hello,
In this case, we could considering this as a redox titration:

Thus, the balance turns out (by adding both hydrogen ions and water):

Thus, by stoichiometry, the grams of Fe+2 ions result:

Finally, the mass percent is:

Best regards.