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bixtya [17]
3 years ago
13

"a reaction was performed in which 0.57 g of 2-naphthol was reacted with a slight excess of 1-bromobutane to make 0.32 g of 2-bu

toxynaphthalene. calculate the theoretical yield and percent yield for this reaction."
Chemistry
1 answer:
murzikaleks [220]3 years ago
8 0
Convert 0.47g 2-naphthol to mols. mol = g/molar mass. 
Using the coefficients in the balanced equation, convert mols 2-naphthol to mols 2-butoxynaphthalene then you have to Convert mol 2-butoxynaphthalene to grams. g = mols x molar mass. This is the theoretical yield. 
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Can the crabs see the plankton they eat near the ocean floor?
cricket20 [7]

Answer:

Explanation:

The crabs cannot see the plankton they eat near the ocean floor. For the crabs to see the plankton, some color of visible light would need to reach the plankton so that it can be reflected into the crabs' eyes.

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What happens in a condensation reaction?
Agata [3.3K]

A) Head to tail joining of monomers. :) (confirmed correct answer, I took the test)

8 0
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The density of ethanol is 0.789 g/cm^3 at 20 degrees C. What volume of ethanol has a mass of 15.5 grams?
lys-0071 [83]
<span>density = mass / volume
   
given the quotient , we have density and mass, volume can be easily calculated as:
   
volume = mass / p =15.5 g / 0.789 g/cm^3
   
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6 0
3 years ago
The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: E = R_y/n^2 In this equation R_y stands
Katarina [22]

Answer:

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is 5.23\times 10^{-5} m

Explanation:

Given :

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:

E=\frac{R_y}{n^2}

R_y=2.18\times 10^{-18} J =  Rydberg energy

n =  principal quantum number of the orbital

Energy of 11th orbit = E_{11}

E_{11}=\frac{2.18\times 10^{-18} J}{11^2}=1.80\times 10^{-20} J

Energy of 10th orbit = E_{10}

E_{10}=\frac{2.18\times 10^{-18} J}{10^2}=2.18\times 10^{-20} J

Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.

E'=E_{10}-E_{11}=2.18\times 10^{-20} J-1.80\times 10^{-20} J

=E'=0.38\times 10^{-20} J

\lambda =\frac{hc}{E'} (Planck's' equation)

\lambda = \frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{0.38\times 10^{-20} J}

\lambda = 5.2310\times 10^{-5} m\approx 5.23\times 10^{-5} m

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is 5.23\times 10^{-5} m

3 0
2 years ago
Why is ethanol a member of the homologous series of alcohols but propane is not<br> I’m in the exam!
Mumz [18]

Answer:

I hope it helps..... you can stop at the full-stop

3 0
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