Answer:
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Explanation:
Answer:
Surface charge density will be ![3.812\times 10^{-6}C/m^2](https://tex.z-dn.net/?f=3.812%5Ctimes%2010%5E%7B-6%7DC%2Fm%5E2)
Explanation:
We have given speed of the belt v = 43 m/sec
Width of the belt w = 61 cm
We know that charge is equal to Q = It, here Is current and t is time
And time is equal to
, here L is distance and v is speed
Putting the value of t in charge equation
![Q=i\times \frac{L}{v}=\frac{iL}{v}](https://tex.z-dn.net/?f=Q%3Di%5Ctimes%20%5Cfrac%7BL%7D%7Bv%7D%3D%5Cfrac%7BiL%7D%7Bv%7D)
Surface charge density is equal to ![\sigma =\frac{Q}{A}=\frac{iL}{vA}](https://tex.z-dn.net/?f=%5Csigma%20%3D%5Cfrac%7BQ%7D%7BA%7D%3D%5Cfrac%7BiL%7D%7BvA%7D)
We know that width is equal to ![w=\frac{A}{L}](https://tex.z-dn.net/?f=w%3D%5Cfrac%7BA%7D%7BL%7D)
So ![\sigma =\frac{i}{vw}=\frac{100\times 10^{-6}}{43\times 0.61}=3.812\times 10^{-6}C/m^2](https://tex.z-dn.net/?f=%5Csigma%20%3D%5Cfrac%7Bi%7D%7Bvw%7D%3D%5Cfrac%7B100%5Ctimes%2010%5E%7B-6%7D%7D%7B43%5Ctimes%200.61%7D%3D3.812%5Ctimes%2010%5E%7B-6%7DC%2Fm%5E2)
Acoustics is the common name ....
Looking out from a vertex with angle θ, sin(θ) is the ratio of the opposite side to the hypotenuse , while cos(θ) is the ratio of the adjacent side to the hypotenuse . No matter the size of the triangle, the values of sin(θ) and cos(θ) are the same for a given θ, as illustrated below.
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Answer:
24 N
Explanation:
Given,
Unstretched length or original length , x1 = 12cm
Stiffness constant, k = 8 N/cm
Load required to take spring to a length , x2 of 15cm
Recall the relation :
F = Ke
Where, e = extension
e = x2 - x1
e = (15 - 12) = 3
F = ke
F = 8 N/cm * 3cm
F = 24 N/cm*cm
F = 24 N
Hence, required load = 24 N