Answer:
Option C. Decomposition
Explanation:
To know which option is correct, it is important we know what is a single displacement reaction, double displacement reaction and decomposition reaction.
A Single displacement reaction can be defined as a reaction in which a single element is replaced by another element in a compound.
A double displacement reaction is a reaction involving the exchange of ions of two parts of ionic compounds to form two different compounds.
A decomposition reaction is a reaction in which a compound splits into two or more simpler compound or element.
Bearing the above definitions in mind and considering the question given above, we can conclude that the reaction given in the question above is a decomposition reaction since the compound (NH₄OH) splits into two different compound (NH₃ and H₂O)
The answer is 2 electrons I believe!
Answer:
5.0 x 10⁹ years.
Explanation:
- It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
- Half-life time is the time needed for the reactants to be in its half concentration.
- If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
- Also, it is clear that in first order decay the half-life time is independent of the initial concentration.
- The half-life of K-40 = 1.251 × 10⁹ years.
- For, first order reactions:
<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>
Where, k is the rate constant of the reaction.
t1/2 is the half-life of the reaction.
∴ k =0.693/(t1/2) = 0.693/(1.251 × 10⁹ years) = 5.54 x 10⁻¹⁰ year⁻¹.
- Also, we have the integral law of first order reaction:
<em>kt = ln([A₀]/[A]),</em>
where, k is the rate constant of the reaction (k = 5.54 x 10⁻¹⁰ year⁻¹).
t is the time of the reaction (t = ??? year).
[A₀] is the initial concentration of (K-40) ([A₀] = 100%).
[A] is the remaining concentration of (K-40) ([A] = 6.25%).
∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = ln((100%)/( 6.25%))
∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = 2.77.
∴ t = 2.77/(5.54 x 10⁻¹⁰ year⁻¹) = 5.0 x 10⁹ years.
Answer: The charge on the plates are 88.4 picafarad
Explanation:The equation used in measuring charge in a plate is given as:
C=Q/V =E A/D
Where E= dielectric content
A= Area of plates
d= distance between plates
Using dielectric constant for Air=8.84×10-12F/m
A=100cm2=0.01m2
d=10mm=0.001m
C= 8.84×10-12×0.01/0.001
C= 88.4 picafarad
