Answer:
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Explanation:
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348.34 m/s. When Superman reaches the train, his final velocity will be 348.34 m/s.
To solve this problem, we are going to use the kinematics equations for constant aceleration. The key for this problem are the equations
and
where
is distance,
is the initial velocity,
is the final velocity,
is time, and
is aceleration.
Superman's initial velocity is
, and he will have to cover a distance d = 850m in a time t = 4.22s. Since we know
,
and
, we have to find the aceleration
in order to find
.
From the equation
we have to clear
, getting the equation as follows:
.
Substituting the values:
![a=\frac{2(850m-54.5\frac{m}{s}.4.22s) }{(4.22s)^{2}}=69.63\frac{m}{s^{2}}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B2%28850m-54.5%5Cfrac%7Bm%7D%7Bs%7D.4.22s%29%20%7D%7B%284.22s%29%5E%7B2%7D%7D%3D69.63%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
To find
we use the equation
.
Substituting the values:
![v_{f} =54.5\frac{m}{s} +(69.63\frac{m}{s^{2}}.4.22s)=348.34\frac{m}{s}](https://tex.z-dn.net/?f=v_%7Bf%7D%20%3D54.5%5Cfrac%7Bm%7D%7Bs%7D%20%2B%2869.63%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D.4.22s%29%3D348.34%5Cfrac%7Bm%7D%7Bs%7D)
The object's speed will not change.
In fact, after the astronaut throws the object, no additional forces will act on it (since the object is in free space). According to Newton's second law:
![\sum F=ma](https://tex.z-dn.net/?f=%5Csum%20F%3Dma)
where the first term is the resultant of the forces acting on the body, m is the mass of the object and a its acceleration, we see that if no forces act on the object, then the acceleration is zero. Therefore, the acceleration of the object is zero, and its velocity remains constant.
(-5)/3 - 6/(-5)
You can solve it now :)
Take a look at a simple reaction like the one below:
In this reaction some reactant A is turned into some product B. The rate of reaction can be represented by a decrease in concentration of A over time or as the increase of B over time. This is written: