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Rudik [331]
3 years ago
8

A ball whose mass is 0.3 kg hits the floor with a speed of 7 m/s and rebounds upward with a speed of 4 m/s. if the ball was in c

ontact with the floor for 1.5 ms (1.5multiply10-3 s), what was the average magnitude of the force exerted on the ball by the floor? favg = 602.94 incorrect: your answer is incorrect. n.
Physics
1 answer:
Maurinko [17]3 years ago
8 0
Newton's second law is stated as:
F=ma,

a = (7-4)/1.5 = 2 m/s^2 (it is a deceleration due to impact with floor. And thus the ball exerts force on the floor).

Therefore,

F= 0.3*2 = 0.6 N
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Is the mass of an object measured with scale, yes or no​
mamaluj [8]

Answer:

No.

Explanation:

The scale actually measures the force that the object does against it, and that force is called the weight.

Such that if we have an object with mass M and we are on Earth, where the gravitational acceleration is g, the weight is:

W = M*g

Now, there is a unit called "kilogram-force"

Such that on Earth, an object that has a mass of 10 kilograms, weighs 10 kilograms-force.

Then from the weight measure, we can instantly know the mass of the object, but the thing that is being measured is the weight, not the mass.

7 0
3 years ago
A trumpeter plays at a sound level of 75dB. three equally loud trumpet players join in. what is the new sound level?​
Serjik [45]
The answer is approx 87 decibels.
6 0
3 years ago
A slice of pizza has 500 kilocalories. If we could burn the pizza and use all the heat to warm a 50 liter container of cold wate
quester [9]

Answer:

10 degree C

Explanation:

Q = 500 kcal = 500 x 1000 x 4.186 J = 2.1 x 10^6 J

V = 50 liter

m = Volume x density = 50 x 10^3 x 1000 = 50 kg

Let ΔT be the rise in temperature.

Specific heat of water = 4186 J/kg C

Q = m x c x ΔT

2.1 x 10^6 = 50 x 4186 x ΔT

ΔT = 10 degree C

4 0
3 years ago
A 1.50-m string of weight 0.0125 N is tied to the ceiling at its upper end, and the lower end supports a weight W. Ignore the ve
Natalka [10]

Answer:

Explanation:

mass of string = .0125 / 9.8

= 1.275 x 10⁻³ kg

Length of string l = 1.5 m .

m = mass per unit length

= ( .1.275 / 1.5) x 10⁻³ kg/m

m = .85 x 10⁻³ kg/m

wave equation: y(x,t) = (8.50 mm)cos(172 rad/m x − 4830 rad/s t)

compare with equation of wave

y(x,t) = Acos(K x − ω t)

ω ( angular velocity ) = 4830 rad/s

k = 172 rad/m

Velocity = ω / k

= 4830/172 m /s

= 28.08 m /s

velocity of wave = \sqrt{\frac{W}{m } }

28.08 = \sqrt{\frac{W}{.85\times10^{-3} } }

788.48 =  W / .85 X 10⁻³

W = 670 x  10⁻³ N .

c ) wave length

wave length =2π  / k

= 2 x 3.14 / 172

= .0365 m

no of wave lengths over whole length of string

= 1.5 / .0365

= 41

d )

equation for waves traveling down the string

= (8.50 mm)cos(172 rad/m x + 4830 rad/s t)

5 0
3 years ago
Consider a car moving with a constant velocity of 90 m/s. What is it’s acceleration.
Troyanec [42]

Answer:

Zero

Explanation:

Acceleration is rate of change of velocity..

5 0
3 years ago
Read 2 more answers
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