Answer:
(for small oscillations)
Explanation:
The total energy of the pendulum is equal to:
![E_{1} = m\cdot g \cdot (1-\cos \theta)\cdot L](https://tex.z-dn.net/?f=E_%7B1%7D%20%3D%20m%5Ccdot%20g%20%5Ccdot%20%281-%5Ccos%20%5Ctheta%29%5Ccdot%20L)
For small oscillations, the equation can be re-arranged into the following form:
![E_{1} \approx m\cdot g \cdot (1-\theta) \cdot L](https://tex.z-dn.net/?f=E_%7B1%7D%20%5Capprox%20m%5Ccdot%20g%20%5Ccdot%20%281-%5Ctheta%29%20%5Ccdot%20L)
Where:
, measured in radians.
If the amplitude of pendulum oscillations is increase by a factor of 4, the angle of oscillation is
and the total energy of the pendulum is:
![E_{2} \approx m\cdot g \cdot (1-4\theta)\cdot L](https://tex.z-dn.net/?f=E_%7B2%7D%20%5Capprox%20m%5Ccdot%20g%20%5Ccdot%20%281-4%5Ctheta%29%5Ccdot%20L)
The factor of change is:
![\frac{E_{2}}{E_{1}} \approx \frac{1 - 4\theta}{1-\theta}](https://tex.z-dn.net/?f=%5Cfrac%7BE_%7B2%7D%7D%7BE_%7B1%7D%7D%20%5Capprox%20%5Cfrac%7B1%20-%204%5Ctheta%7D%7B1-%5Ctheta%7D)
![\frac{E_{2}}{E_{1}} \approx 1 -\frac{3\theta}{1-\theta}](https://tex.z-dn.net/?f=%5Cfrac%7BE_%7B2%7D%7D%7BE_%7B1%7D%7D%20%5Capprox%201%20-%5Cfrac%7B3%5Ctheta%7D%7B1-%5Ctheta%7D)
Aluminum, and magnesium are metals. For metals, reactivity decreases as you go from left to right across the periodic table. Atomic number of Al is 13 and of Mg is 12. Hence the least reactive of these two is therefore aluminum.
Magnesium is "HIGHLY FLAMMABLE" carefully take a small piece and hit it with a torch. If its Magnesium it will "Caution, very, quickly burn.
Aluminum will not react to simple flame, it will only melt with enough direct heat.
Magnesium
==========
Atomic Number: 12
Atomic Symbol: Mg
Atomic Weight: 24.305
Electron Configuration: 2-8-2
Aluminum
========
Atomic Number: 13
Atomic Symbol: Al
Atomic Weight: 26.9815
Electron Configuration: 2-8-3
Hope this helps some. Any questions please feel free to ask. Thank you
An insulator which is also called a 'dielectric'.
1) In a circular motion, the angular displacement
![\theta](https://tex.z-dn.net/?f=%5Ctheta)
is given by
![\theta = \frac{S}{r}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20%5Cfrac%7BS%7D%7Br%7D%20)
where S is the arc length and r is the radius. The problem says that the truck drove for 2600 m, so this corresponds to the total arc length covered by the tire:
![S=2600 m](https://tex.z-dn.net/?f=S%3D2600%20m)
. Using the information about the radius,
![r=0.35 m](https://tex.z-dn.net/?f=r%3D0.35%20m)
, we find the total angular displacement:
![\theta = \frac{2600 m}{0.35 m} =7428 rad](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20%5Cfrac%7B2600%20m%7D%7B0.35%20m%7D%20%3D7428%20rad)
2) If we put larger tires, with radius
![r=0.60 m](https://tex.z-dn.net/?f=r%3D0.60%20m)
, the angular displacement will be smaller. We can see this by using the same formula. In fact, this time we have:
The correct answer should be c.The kinetic energy of the water molecules decreases.
If the temperature drops that means that the molecules are coming together. If the temperature rises then it means that the molecules are spreading. If the kinetic energy falls down that means that they are slower which means that they are cooler.