1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
max2010maxim [7]
2 years ago
11

A 4 kg bowling boll sliding to the right at 8 m/s has elastic head-on collision with another 4K bowling ball initially at rest.

The first bus stops after collision
A. Find the velocity of the second ball after the collision

B. Verifier answered by calculating the total kinetic energy before and after the collision
Physics
1 answer:
MAXImum [283]2 years ago
6 0
The energy would be transferred from the objects. Also do not forget, add direction to your answer.
You might be interested in
How much energy in calories does it take to melt 10 grams of ice?
Nikitich [7]

Answer:

800 calories

Explanation:

3 0
2 years ago
Read 2 more answers
1. How much energy would be required to melt 450 grams of ice at 0°C?
xenn [34]

Answer:

Explanation:

1. The amount of heat needed to melt ice at 0°C is equal to the mass of the ice times the latent heat of fusion.

q = mL

q = (450 g) (334 J/g)

q = 150,300 J

q = 150 kJ

2. The amount of heat released by the condensation of steam at 100°C is equal to the mass of the steam times the latent heat of vaporization.

q = mL

q = (325 g) (2260 J/g)

q = 734,500 J

q = 735 kJ

3. q = mL

q = (85 g) (2260 J/g)

q = 192,100 J

q = 190 kJ

4. q = mL

q = (225 g) (334 J/g)

q = 75,150 J

q = 75.2 kJ

5. Above 100°C, water is steam.  The amount of heat needed to increase the temperature of steam is equal to its mass times its specific heat times the change in temperature.

q = mCΔT

q = (20.0 g) (2.03 J/g/°C) (303.0°C − 283.0°C)

q = 812 J

6. q = mCΔT

q = (15.0 g) (2.03 J/g/°C) (250.0°C − 275.0°C)

q = -761 J

7. q = mCΔT

q = (10.0 g) (0.90 J/g/°C) (55°C − 22°C)

q = 297 J

8. q = mCΔT

198 J = (55.0 g) C (15°C)

C = 0.24 J/g/°C

9. q = mCΔT

41,840 J = m (4.184 J/g/°C) (28.5°C − 22.0°C)

m = 1540 g

10. q = mCΔT

q = (193 g) (2.46 J/g/°C) (35°C − 19°C)

q = 7600 J

11. First, the temperature of the ice must be raised to 0°C.

q = mCΔT

q = m (2.09 J/g/°C) (0°C − (-23.0°C))

q/m = 48.1 J/g

Next, the ice must be melted.

q = mL

q/m = 334 J/g

Then, the water must be heated to 100°C.

q = mCΔT

q = m (4.184 J/g/°C) (100°C − 0°C)

q/m = 418.4 J/g

The water is then vaporized.

q = mL

q/m = 2260 J/g

Finally, the steam is heated to its final temperature.

q = mCΔT

q = m (2.03 J/g/°C) (118°C − 100°C)

q/m = 36.5 J/g

So the total amount of energy needed is:

q/m = 48.1 J/g + 334 J/g + 418.4 J/g + 2260 J/g + 36.5 J/g

q/m = 3100 J/g

3 0
2 years ago
ANSWER FAST PLEASE!
labwork [276]

Answer:

When friction hits the floor, the oil bounces back up but then down. Then the oil spreads apart. Like an earthquake. Not really though. And try not to spill oil for the first place.

Hope I helped! Brainiest plz! Hope you make an 100% and have a wonderful day! -Amelia♥

4 0
2 years ago
Calculate the force of gravity on the 0.60- kg mass if it were 1.3×107 m above Earth's surface (that is, if it were three Earth
nignag [31]
The gravitational force between two objects is given by:
F=G \frac{m_1 m_2}{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is their separation

In this problem, the first object has a mass of m_1=0.60 kg, while the second "object" is the Earth, with mass m_2=5.97 \cdot 10^{24}kg. The distance of the object from the Earth's center is r=1.3 \cdot 10^7 m; if we substitute these numbers into the equation, we find the force of gravity exerted by the Earth on the mass of 0.60 kg:
F=G \frac{m_1m_2}{r^2}=(6.67\cdot 10^{-11}) \frac{(0.60 kg)(5.97 \cdot 10^{24} kg)}{(1.3 \cdot 10^7 m)^2}=  1.41 N
5 0
3 years ago
You and your friends are having a discussion about weight. He/she claims that he/she weighs less on the 100th floor of a buildin
Viktor [21]

Answer:

if the weight theoretically decreases at this height, but in a fraction of 10⁻⁵, which is not appreciable in any scale, therefore, the reading of the scale in the two places is the same.

Explanation:

The weight of a person in the force with which the Earth attracts the person, therefore can be calculated using the law of universal attraction

          F = G m M / r²

Where m is the mass of the person, M the masses of the earth

Let's call the person's weight at ground level as Wo and suppose the distance to the center of the Earth is Re

            W₀ = G m M / Re²

In the calculation of the weight of the person on the 100th floor the only thing that changes is the distance

          r = Re + 100 r₀

Where r₀ is the distance between the floors, which is approximately 2.5 m, so the distance is

         r = Re + 250

We substitute

     W = G m M / r²

      W = G m M / (Re + 250)²

The value of Re is 6.37 10⁶ m, so we can take it out as a factor and perform a serial expansion of the remaining fraction

      W = G m M / Re² (1+ 250 / Re)²

      (1 + 250 / Re)⁻² = 1 + (-2) 250 / Re + (-2 (-2-1)) / 2 (250 / Re)² +….

The value of the expression is

      (1 + 250 / Re)⁻² = 1 -2 250 / 6.37 10⁶ -30 (250 / 6.37)² 10⁻¹² + ...

We can see that the quadratic term is very small, which is why we despise it, we substitute in the weight equation

      W = G m M / Re² (1 - 78.5 10⁻⁶)

Remains

     W = Wo (1 - 7.85  10⁻⁵)

We can see that if the weight theoretically decreases at this height, but in a fraction of 10⁻⁵, which is not appreciable in any scale, therefore, the reading of the scale in the two places is the same.

4 0
3 years ago
Read 2 more answers
Other questions:
  • Can you convert 80 mg to kg
    9·1 answer
  • Please help me answer this science question
    12·2 answers
  • What is the word for the definition of an electron in the highest occupied energy level of an atom
    6·1 answer
  • Draw distance time grap for a body at rest
    10·1 answer
  • The above Free Body Diagram represents the motion of a toy car across a floor from left to right. The weight of the .5 kg car is
    12·1 answer
  • Scientists review the work of other scientists to. . A) ensure the results are in agreement with accepted scientific beliefs. .
    9·2 answers
  • Most stars are<br> a.brown fs<br> b.main sequence<br> c.white dwarfs<br> d.pulsars
    15·1 answer
  • Pls give motivation, a paragraph pls! I'll give brainliest to whoever's is the biggest and best! I'll give 50 points, it is for
    13·1 answer
  • Please answer 11-13. say if i'm right for 10 if you can.
    11·1 answer
  • 1.A virtual image is formed 20.5 cm from a concave mirror having a radius of curvature of 31.5 cm.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!