All categories

3 years ago

Define the term acceleration due to gravity

Physics

1 answer:

kifflom [539]3 years ago

7 0

Answer

Acceleration

Acceleration Means rate of Change of velocity with respect to time.

acceleration due to gravity

when a body falls freely means no other force act on it except gravitational force that time velocity of object does not remains constant but it changes as it approaches towards the ground it means body get accelerated and this acceleration which is gained by the body due to gravitational force is called its acceleration due to gravity it is denoted by g. Acceleration due to gravity is different on different planet. SI unit of is m/s^2 . On earth its standard value is 9.80665m/s^2.

You might be interested in

On a visit to a science lab, Madison observes a blob of shiny material that is floating in the air.

AfilCa [17]

Answer:

Each force acting on the blob has another one to cancel it out

Explanation:

7 0

3 years ago

Read 2 more answers

Brent made the table shown to discribe two different relationships between animals.

grigory [225]

i think it is the second one due to the preditory descritpion of relationship A

5 0

4 years ago

An object moving in circular motion has a mass of 15 kg and a centripetal acceleration of 10 m/s2. What is the centripetal force

sweet-ann [11.9K]

Answer:

1) A

2) C

3) B

4) A

5) Incomplete information(picture missing)

6) Incomplete information(picture missing)

7) Incomplete information(picture missing)

8) A

9) C

10) C

Explanation:

1) m = 15kg, a = $10ms^{-2}$ , F = ma = 15*10 = 150N

2) m = 3kg, v = $4ms^{-1}$ , r = 4m, F = $\frac{mv^{2} }{r}$

$\frac{3*4^{2} }{4}$ = 12N

3) a = $10ms^{-2}$ , r = 10m, v=?

F = $\frac{mv^{2} }{r}$ and F = ma

equating the two equations and cancelling a, we have:

$\frac{v^{2} }{r}$ = a

making v the subject of formula, we have:

v = $\sqrt{ar}$

= $\sqrt{100}$

= 10 $ms^{-1}$

4) r = 10m, v = $5ms^{-1}$ , a = ?

F = $\frac{mv^{2} }{r}$

F = ma

equating the above equations and making a subject of formula, we get:

a = $\frac{v^{2} }{r}$

a = 25/10 = 2.5 $ms^{-2}$

5) I can't find the picture associated with this question

6) I can't find the picture associated with this question

7) I can't find the picture associated with this question

8) F = $\frac{mv^{2} }{r}$

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = $v^{2}$

Now, if v is tripled

F = $(3v)^{2}$

F = 9 $v^{2}$

We can see that the force will be 9X greater than it was.

9) F = $\frac{mv^{2} }{r}$

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = $v^{2}$

Now, if v is doubled

F = $(2v)^{2}$

F = 4 $v^{2}$

We can see that the force will be 4X greater than it was.

10) F = $\frac{mv^{2} }{r}$

assuming m and v is unity, that is the values are 1 respectively

F = 1/r

if r is doubled,

F = 1/2 * 1/r

We can see that the force is 1/2 as big as it was

7 0

3 years ago

A student stands with both feet on some scales in order to measure his weight.

Neko [114]

Answer:

500 N

Explanation:

Because even if he lift one foot his weight will be same as the pressure applied on the scale will be the same and will not change it is not that the scale measures each foot separately

3 0

3 years ago

A magician quickly pulls on a tablecloth and the items remain in place.Why does this happen

____ [38]

Newton's first law says that the tableware will remain motionless unless acted upon by an outside force.

5 0

3 years ago