You determined that Cr2O3 is the limiting reactant in the reaction below. If the reaction begins with85.00 grams of Cr2O3 and157
1 answer:
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Answer:
<h2>73.53 mL</h2>Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question we have
We have the final answer as
<h3>73.53 mL</h3>Hope this helps you
Answer:
<h2>1.38 moles</h2>Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>1.38 moles</h3>Hope this helps you
Please, find the complete question in the picture attached.
Answer:
1. Na₂O
2. AlF₃
3. MgO
4. Ca₃P₂
Explanation:
1. Na⁺ and O²⁻
An ionic compound will be formed when two ions of opposite charge attract each other.
The positive ion is called cation and the negative ion is called anion.
Thus, every ionic compound has a cation and an anion electrostatically bonded.
The ions must combine in a proportion that genders a neutral compound: so you must have as many cations as negative charge has one anion and as many anions as positive charge has one cation.
This is, if the cation has charge +x, there will be x anions, and if the anion has charge -y, there will be y cations.
Simbolically:
As you see, the subscripts for each element in the chemical formula are obtained by the exchage of the charges of the ions.
Then, for Na⁺ and O²⁻, the subscript for Na will be 2 and the subscript for O will be 1; and the formula of the ionic compound formed by this pair ot ions is:
- Na₂O
2. Al³⁺ and F⁻
- The subscript of Al will be 1 (because the F ion has charge 1-, and the subscript of F will be 3 (because the Al ion has charge +3).
Thus the ionic compound formed by this pair of ions is:
- AlF₃
3. Mg²⁺ and S²⁻
- The charge 2+ from Mg atom wil become the subscript 2 of S atom, and the charge 2- will become the subscript 2 of Mg atom:
That results in the formula: Mg₂S₂
Except for some special compounds, the chemical formula is simplified, dividing by the least common denominator. In this case, that means that the two 2 subscripts are simplified to 1, and the final chemical formula for the ionic compound formed by this pair of ions is:
- MgO
4. Ca²⁺ and P³⁻
- The charge 2+ from Ca will become subscript 2 for P and the charge 3- whill become subscript 3 for Ca.
Hence, the ionic compound formed by these two ions is:
- Ca₃P₂
