Explanation:
a car exccelerate at rate of 3.0m/sec 2
Answer:
4.44m/s
Explanation:
Given parameters:
Number of laps = 4
Length of track = 400m
Time taken = 6min
Unknown:
Average speed = ?
Solution:
The average speed is the total distance covered divided by the time taken.
It is mathematically expressed as;
Average speed =
Total distance = number of laps x length of track = 4 x 400 = 1600m
Now convert the time to seconds;
60s = 1 min
6 minutes will be 6 x 60 = 360s
So;
Average speed =
= 4.44m/s
Answer:
3.72 kJ
Explanation:
QH = 6.45 kJ
TH = 520 K
Tc = 300 K
Qc = ?
By use of Carnot's theorem
Qc / QH = Tc / TH
Qc / 6.45 = 300 / 520
Qc = 3.72 kJ
Answer:
Explanation:
Given
Initial velocity u = 200m/s
Final velocity = 4m/s
Distance S = 4000m
Required
Acceleration
Substitute the given parameters into the formula
v² = u²+2as
4² = 200²+2a(4000)
16 = 40000+8000a
8000a = 16-40000
8000a = -39,984
a = - 39,984/8000
a = -4.998m/s²
Hence the acceleration is -4.998m/s²