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sattari [20]
3 years ago
8

The astronomer Kepler develop the three laws a planetary motion what is meant by the love distance. Relationship

Physics
1 answer:
Mila [183]3 years ago
4 0

Explanation:

iwan anonanswwee hahhahah ambroyttnHhHaHhahahahahahaha yab angajqiwwieidjdndndndnd

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50 mL of soda in a soda can exerts ____ 50 mL of soda in a 1L bottle.
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More pressure than..



4 0
3 years ago
Rusty Pickins, a gold miner, has just found a chunk of gold. Rusty would like to change the gold from a solid to a liquid, so th
Vitek1552 [10]
<span>b.) Add heat to increase the molecular motion of the atoms</span>
5 0
4 years ago
On a roller coaster ride the total mass of a cart - with two passengers included - is 319 kg. Peak K is at 43.6 m above the grou
Dafna1 [17]

The mechanical energy is lost due to friction between the two peak is 78,458.688 J

<h3>What is mechanical energy?</h3>

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

Given is a roller coaster ride the total mass of a cart - with two passengers included - is 319 kg. Peak K is at 43.6 m above the ground and peak L is at 24.4 m. At location K the speed of the cart is 16.4 m/s, and at location L it is 12.4 m/s.

Total energy at peak K,

TE₁ = 1/2 mv₁² +mgh₁

Substitute the values, we get

TE₁ =  1/2 x319 x 16.4² +319 x 9.81 x 43.6

TE₁ = 179,340. 524 J

Total energy at peak L,

TE₂ = 1/2 mv₂² +mgh₂

Substitute the values, we get

TE₂ =  1/2 x319 x 12.4² +319 x 9.81 x 24.4

TE₂ = 100,881. 836 J

The mechanical energy lost is

M.E =  TE₁ -TE₂

M.E =  179,340. 524 J -  100,881. 836 J

M.E = 78,458.688 J

Thus, the mechanical energy is lost due to friction between the two peak i

Learn more about mechanical energy.

brainly.com/question/13552918

#SPJ1

7 0
2 years ago
2. Can you place three forces of 5g, 6g, and 12g so they are in equilibrium. Justify your answer.
Bond [772]

Answer:

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

Explanation:

Equilibrium means their sum must be zero.

Here the forces are 5g, 6g, and 12g.

For number of forces to be in equilibrium the magnitude of largest vector should be less than sum of the magnitude of other vectors.

Here

        Magnitude of largest force = 12 g

        Sum of magnitudes of other forces = 5g + 6g = 11g

       Magnitude of largest force >   Sum of magnitudes of other forces

So this forces cannot form equilibrium.

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

4 0
3 years ago
A 1400-kg car is moving at a speed of 25m/s. how much kinetic energy does the car have?
Luba_88 [7]

Answer:

437.5Kjoules

Explanation:

K.E=half multiply by mass multiply by square of velocity

=437.5Kjoules

3 0
3 years ago
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