1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mariulka [41]
3 years ago
15

Consider the unbalanced equation for the oxidation of aluminum. _Al + _O2 ------> _Al2O3 Which sequence of coefficients shoul

d be placed in the blanks to balance this equation? * 2 points 2,3,1 1,3,2 4,3,2 3,2,3
Chemistry
1 answer:
Nimfa-mama [501]3 years ago
6 0

Answer:

4Al + 3O2-> 2Al2O3 :))))

You might be interested in
The difference between An atom and an element <br>​
andreev551 [17]

Answer:

there is your answer hopefully it helps you out

5 0
3 years ago
Haber was able to manufacture large amounts of ammonia, what do plants convert ammonia into?
suter [353]

Answer:

Nitrates.

Explanation:

They convert ammonia to nitrates.

3 0
3 years ago
H2O2+CLO2====CLO-2+O2.​ Balance the equation using half reaction
zavuch27 [327]

Answer:

I have the explanation.

Explanation:

5 0
2 years ago
Which statements regarding the Henderson-Hasselbalch equation are true? If the pH of the solution is known as is the pKa for the
Sonbull [250]

Answer:

1, 2, and 3 are true.

Explanation:

The Henderson-Hasselbalch equation is:

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

  • If the pH of the solution is known as is the pKa for the acid, the ratio of conjugate base to acid can be determined. <em>TRUE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

If you know pH and pka:

10^(pH-pka) = \frac{[A^-]}{[HA]}

The ratio will be: 10^(pH-pka)

  • At pH = pKa for an acid, [conjugate base] = [acid] in solution. <em>TRUE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

0 = log₁₀ \frac{[A^-]}{[HA]}

10^0 = \frac{[A^-]}{[HA]}

1 = \frac{[A^-]}{[HA]}

As ratio is 1,  [conjugate base] = [acid] in solution.

  • At pH >> pKa for an acid, the acid will be mostly ionized. <em>TRUE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

If pH >> pKa,  10^(pH-pka) will be >> 1, that means that you have more [A⁻] than [HA]

  • At pH << pKa for an acid, the acid will be mostly ionized. <em>FALSE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

If pH << pKa,  10^(pH-pka) will be << 1, that means that you have more [HA] than [A⁻]

I hope it helps!

6 0
3 years ago
If 35.8 grams of LiCl are dissolved in 184 grams of water, what is the concentration of the solution in percent by mass?
joja [24]
14% mass per inch squared
3 0
3 years ago
Other questions:
  • What is the concentration of a 0.750 l solution that contains 52.0 g of glucose (c6h12o6)?
    7·1 answer
  • What is the oxidation number for iodine in Mg(IO3)2 ?
    13·2 answers
  • NH3 is nitrogen trihydride (ammonia) and BF3 is boron trifluoride. What is the name for AlCl3 and why?
    7·1 answer
  • LiNO3(aq) and Na2CO3(aq).If a solid forms when solutions containing these salts are mixed, write the ionic equation.
    5·2 answers
  • Write the concentration equilibrium constant expression for this reaction.
    11·1 answer
  • How many zinc atoms are there in 65.4 g?
    7·1 answer
  • Which law states that the volume and absolute temperature of a fixed quantity of gas are directly proportional under constant pr
    7·1 answer
  • PLEASE HELP!!!! WILL GIVE BRANLIEST!!
    7·2 answers
  • Help help help help help
    10·1 answer
  • What is the mass in grams for a piece of lead that has a volume of 14.8 cubic centimeters? The density of lead is 11.4 g/cc.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!