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2 years ago

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Which of the following has the greatest mass, in grams?1) 1 atom of gold (Au) 2) 1.0 mol mercury (Hg) atoms 3) 2.0 mole of chlor

ine (Cl) atoms 4) 25 atoms of mercury (Hg)

1 answer:

vlada-n [284]2 years ago

3 0

c is the answer for ur question

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A waterbed filled with water has the dimensions 8.5ft by 7.5ft by 9.5inches. Taking the density of water to be 1.00 g/cubic cent

Citrus2011 [14]

First, 1 foot = 30.48cm (12 inches x 2.54 cm/inch=30.48 cm). So, 8,5 ft = 8.5 x 30.48cc=259.08 cm, 7.5 ft = 7.5 x 30.48=228.6cm and 9.5/12=0.791ft x 30.48 =24.11cm. So, in cc, 259.08 x 228.6 x 24.11 = 1,427,931.3 cc. Since 1 cc of water = 1 gram then we have 1,427,931`grams or 1427. 931 kg x 2.2 lbs/kg = 3141 pounds of water or 1.57 tonnes of water so with this size of waterbed if upstairs the house structure must be able to withstand this stress.

3 0

3 years ago

Consider the reaction Mg₂Si(s) + 4 H₂O(ℓ) → 2 Mg(OH)₂(aq) + SiH₄(g). How many grams of silane gas (SiH₄) are formed if 25.0 g of

Neko [114]

Answer:

10.60 grams of silane gas are formed.

Explanation:

From the reaction:

Mg₂Si(s) + 4H₂O(l) → 2Mg(OH)₂(aq) + SiH₄(g)

We know that the limiting reactant is Mg₂Si, so to find the mass of SiH₄ formed we need to calculate the number of moles of Mg₂Si:

$\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}}$

Where:

m: is the mass of Mg₂Si = 25.0 g

M: is the molar mass of Mg₂Si = 76.69 g/mol

$\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}} = \frac{25.0 g}{76.69 g/mol} = 0.33 moles$

Now, the stoichiometric relation between Mg₂Si and SiH₄ is 1:1 so:

$\eta_{Mg_{2}Si} = \eta_{SiH_{4}} = 0.33 moles$

Finally, the mass of SiH₄ is:

$m_{SiH_{4}} = \eta_{SiH_{4}}*M_{SiH_{4}} = 0.33 moles*32.12 g/mol = 10.60 g$

Therefore, 10.60 grams of silane gas are formed.

I hope it helps you!

3 0

2 years ago

How do you find concentration from absorbance mg and ml?

sweet-ann [11.9K]

Great question, let me know if you get the anwser!

8 0

3 years ago

If you start with 6 mol of nitrogen gas (N2+) what mass (g) of ammonia (NH4) will be produced?

Yanka [14]

Answer:

204g of NH3

Explanation:

The balanced equation for the reaction is given below:

N2 + 3H2 —> 2NH3

Next, we shall determine the number of mole NH3 produced by reacting 6moles of N2. This is illustrated below:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 6 moles of N2 will react to produce = 6 x 2 = 12 moles of NH3.

Finally, we shall convert 12 moles of NH3 to grams. This is illustrated below:

Number of mole of NH3 = 12 moles.

Molar mass of NH3 = 14 + (3x1) = 17g/mol

Mass of NH3 =..?

Mass = mole x molar mass

Mass of NH3 = 12 x 17

Mass of NH3 = 204g.

Therefore, 204g of NH3 will be produced from the reaction.

3 0

2 years ago

2 attempts left Click the "draw structure" button to launch the drawing utility. Draw one product formed when the following dien

Yuliya22 [10]

Answer:

2-chloro-1-methyl-cyclohex-1,4-diene.

Explanation:

Hello,

In this case, the addition of hydrochloric acid acts as an electrophilic atack in which the hydrogen bonded to the double-bonded carbon connected to the carbon with the methyl substitution is substituted by the chlorine from the hydrochloric acid, in such a way, 2-chloro-1-methyl-cyclohex-1,4-diene is produced as one equivalent of HCl is used therefore one substitution will be attained for chlorine, and hydrogen as a side product as shown on the attached picture.

Best regards.

7 0

2 years ago