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trasher [3.6K]
3 years ago
14

Which of the following has the greatest mass, in grams?1) 1 atom of gold (Au) 2) 1.0 mol mercury (Hg) atoms 3) 2.0 mole of chlor

ine (Cl) atoms 4) 25 atoms of mercury (Hg)
Chemistry
1 answer:
vlada-n [284]3 years ago
3 0

c is the answer for ur question

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Find the element, mass number, atomic number, and number of protons from the following information.
Klio2033 [76]

Explanation:

Element: Carbon

Mass number: 12

atomic number: 6

No of protons : 6

8 0
3 years ago
What is the uncertian digit in 0.054 g
UkoKoshka [18]

Answer:

5.4g

Explanation:

8 0
3 years ago
Identify the atoms that are oxidized and reduced, the change in the oxidation state for each, and oxidising and reducing agents
KATRIN_1 [288]

Answer:

Explanation:

a) Mg + NiCl_2 \rightarrow MgCl_2 + Ni

Oxidation state of Mg changes to 0 to +2.

Oxidation state of Ni changes to +2 to 0.

Oxidation state of Cl does not change.

So, Mg is oxidized, Ni is reduced.

Mg acts as reducing agent and NiCl_2 acts as oxidizing agent.

b) PCl_3 + Cl_2 \rightarrow PCl_5

Oxidation state of P changes to +3 to +5.

Oxidation state of Cl changes to 0 to -1.

So,

P is oxidized and Cl is reduced.

PCl_3 acts as reducing agent and Cl_2 acts as oxidizing agent.

c) C_2H_4 + 3O_2 \rightarrow 2CO_2 + 2H_2O

Oxidation state of C changes to -2 to +4.

Oxidation state of O changes to 0 to -2.

Oxidation state of H does not change.

So,

C is oxidized and O is reduced.

C_2H_4 acts as reducing agent and O_2 acts as oxidizing agent.

d) Zn + H_2SO_4 \rightarrow ZnSO_4 + H_2

Oxidation state of Zn changes to 0 to +2.

Oxidation state of H changes to +1 to 0.

Oxidation state of S and O do not change.

So, Zn is oxidized, H is reduced.

Zn acts as reducing agent and H_2SO_4 acts as oxidizing agent

e) K_2S_2O_3 + I_2 \rightarrow K_2S_4_O6 + 2KI

Oxidation state of S changes to +2 to +2.5.

Oxidation state of I changes to 0 to -1.

Oxidation state of K and O do not change.

So, S is oxidized, I is reduced.

K_2S_2O_3 acts as reducing agent and I_2 acts as oxidizing agent.

f) 3Cu + 8HNO_3 \rightarrow 3Cu(NO_3)_2 + 4H_2O+2NO

Oxidation state of Cu changes to 0 to +2.

Oxidation state of N changes to N +5 to +2.

Oxidation state of H and O do not change.

So, Cu is oxidized, N is reduced.

Cu acts as reducing agent and HNO_3 acts as oxidizing agent

8 0
2 years ago
What state of matter has no visible shape and fills its container?
Ilia_Sergeevich [38]
I believe it is b. I hope this helps you
8 0
2 years ago
Read 2 more answers
Can someone answer this?
yulyashka [42]

No se si aun necesitas ayuda o no

3 0
2 years ago
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